IGCSE/GCSE/O & A Level/IB/University Student Forum
Qualification => Subject Doubts => GCE AS & A2 Level => Math => Topic started by: nid404 on October 16, 2010, 06:18:59 am
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the 2nd part of the attached question, I dunno why I am not confident abt my answer. I don't have the mark scheme, so I want to confirm my answer with you guys.
I get P as 13.2 N...If someone could verify the answer, it would be great :)
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I'll do it.
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Is coefficient of friction 0.5 ? Did you get that ?
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Is coefficient of friction 0.5 ? Did you get that ?
yup
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Okay, I think your answer is wrong.
This is what I did for the last part.
R - Pcos60 - 3g = 0
hence, R = Pcos60 + 3g
Next, Pcos30 - 0.5(Pcos60 + 3g) = 0
Hence P = 23.9 N
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I did this in a hurry as I have to go for breakfast. Tell me if you think I'm right/wrong.
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Oh yes
R will be the sum of 3g and Pcos 60.
I took R as 3g-Pcos60 I didn't see the direction of the force. My bad.
Thanks ;)
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No worries.
I find it easier if you draw a set of axis and draw in the force vectors.
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I feel lazy :P And end up making silly mistakes >:(
Okay I want to cross check my answers for this one too. Just post the answers. If they differ, then you need to take the pains to type the whole thing :P, else not ;D
Take your time ::)
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Did you read my PM ?
Which year is this from ?
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I'm on it.
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Did you read my PM ?
Which year is this from ?
Yeah I replied...check check!!
June 2005 M1
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http://www.xtremepapers.net/OCR/Maths/2005%20Jun/L_A_Level_Maths_MS_Jun_05.pdf (http://www.xtremepapers.net/OCR/Maths/2005%20Jun/L_A_Level_Maths_MS_Jun_05.pdf)
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I got them right :D
Thanks ;D
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By the way it was jan...i got the ms for it ;D thanks for the ocr directory...I should ask astar to upload them on FEP too
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Congo ;) Glad you've got the MS now. Yeah. We should have them on FEP.
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the 4th part...I don't really understand what they're asking for :S
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the 4th part...I don't really understand what they're asking for :S
When A strikes the ground, B continues to rise against gravity until it reaches its maximum point where v = 0. Then B starts to descend due to its weight. String becomes taut again when B reaches the level it started to rise against gravity, i.e at the time when A touched the ground earlier.
In other words, you need to find the time taken the particle B takes to reach its maximum height as from when A strikes the ground. Multiply it by 2 since for the string to become taut again, B covers twice this distance(once upwards and then downwards) and during the same time.
For the required solution you need to add the value you obtain to your answer in part(ii) :D
Hope it helps :)
If you still cannot do it, let me know ;)
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When A strikes the ground, B continues to rise against gravity until it reaches its maximum point where v = 0. Then B starts to descend due to its weight. String becomes taut again when B reaches the level it started to rise against gravity, i.e at the time when A touched the ground earlier.
In other words, you need to find the time taken the particle B takes to reach its maximum height as from when A strikes the ground. Multiply it by 2 since for the string to become taut again, B covers twice this distance(once upwards and then downwards) and during the same time.
For the required solution you need to add the value you obtain to your answer in part(ii) :D
Hope it helps :)
If you still cannot do it, let me know ;)
Ah I got it :D Thank youu ;D