IGCSE/GCSE/O & A Level/IB/University Student Forum

Qualification => Subject Doubts => GCE AS & A2 Level => Math => Topic started by: missbeautiful789 on October 11, 2010, 04:40:08 pm

Title: CIE AS P1 Math Problem M/J 2010
Post by: missbeautiful789 on October 11, 2010, 04:40:08 pm: Please help me with this math problem, im doing AS, so don't use some funky A2 compound angle equations and shtuff.

see question attached, there just 1 mark each. so 3 quick questions

Thank you in advance
Title: Re: CIE AS P1 Math Problem M/J 2010
Post by: nid404 on October 11, 2010, 05:24:15 pm: Quote from: missbeautiful789 on October 11, 2010, 04:40:08 pm
Please help me with this math problem, im doing AS, so don't use some funky A2 compound angle equations and shtuff.

see question attached, there just 1 mark each. so 3 quick questions

Thank you in advance

You need to know the functions

tan( $(\pi-\theta)$ =-k

tan $\ (1/2pi-\theta)$ = 1/k

sin x= cosx X k
Title: Re: CIE AS P1 Math Problem M/J 2010
Post by: S.M.A.T on October 11, 2010, 05:45:42 pm: U must now this common relation:
sin(180-x)=sinx ,
cos(180-x)=-cosx,
sin(90-x)=cosx
cos(90-x)=sinx
Title: Re: CIE AS P1 Math Problem M/J 2010
Post by: Deadly_king on October 11, 2010, 05:58:44 pm: Quote from: asiftasfiq93 on October 11, 2010, 05:45:42 pm
U must now this common relation:
sin(180-x)=sinx ,
cos(180-x)=-cosx,
sin(90-x)=cosx
cos(90-x)=sinx

+ rep Asif

This question........especially the third one was haunting my mind as well ;)
Title: Re: CIE AS P1 Math Problem M/J 2010
Post by: nid404 on October 11, 2010, 06:00:47 pm: oh only in terms of k :/ My bad.

+ rep asif :)
Title: Re: CIE AS P1 Math Problem M/J 2010
Post by: missbeautiful789 on October 11, 2010, 07:40:09 pm: Oh shucks...i could have used that quadrant angle thingy majig.
trig bones.

Thanks guys, - thank you Asif
Title: Re: CIE AS P1 Math Problem M/J 2010
Post by: S.M.A.T on October 11, 2010, 09:58:52 pm: Quote from: Deadly_king on October 11, 2010, 05:58:44 pm
+ rep Asif

This question........especially the third one was haunting my mind as well ;)

Thanks for +rep :)
i was also stuck with the third one but after thinking for a while i found out how to do it ;D

Garfield:thank U ;D
missbeautiful789:U welcome :D
Title: Re: CIE AS P1 Math Problem M/J 2010
Post by: rocker on October 12, 2010, 08:08:40 am: Another method
Consider the right angle triangle with x angle.let triangle be ABC WITH AC hypotenuse.THE
Tan X =BC/AB
k=Bc/AB
Bc=kAB
how find Ac by using paythagrous therom which gives Ac^2=Bc^2+AB^2
and AC=bc(k^2+1)^(1/2)
now use sIN x=BC/Ac
put value of Ac and Bc=KAB it will give you
sin x=K/(K^2+1)^1/2
thank you
ITseems like complicated but try by drying triangle.
Title: Re: CIE AS P1 Math Problem M/J 2010
Post by: Deadly_king on October 13, 2010, 11:57:25 am: Quote from: rocker on October 12, 2010, 08:08:40 am
Another method
Consider the right angle triangle with x angle.let triangle be ABC WITH AC hypotenuse.THE
Tan X =BC/AB
k=Bc/AB
Bc=kAB
how find Ac by using paythagrous therom which gives Ac^2=Bc^2+AB^2
and AC=bc(k^2+1)^(1/2)
now use sIN x=BC/Ac
put value of Ac and Bc=KAB it will give you
sin x=K/(K^2+1)^1/2
thank you
ITseems like complicated but try by drying triangle.

yeah.......I got it :)

It's indeed easier and simpler ;)

+rep to you as well