IGCSE/GCSE/O & A Level/IB/University Student Forum
Qualification => Subject Doubts => GCE AS & A2 Level => Math => Topic started by: houmeira on September 23, 2010, 05:21:59 pm
-
can anyone help me with this question please?
Find the equation of the curve which passes through the point (1,6)
and for which dy/dx=(1/sqrt x)(x-2/2x)
i can't integrate it:(
-
can anyone help me with this question please?
Find the equation of the curve which passes through the point (1,6)
and for which dy/dx=(1/sqrt x)(x-2/2x)
i can't integrate it:(
Well am not sure.......it would be nice if someone could confirm the answer.
I got....... y = x1/2 + 2/x1/2 + 3
First you need to multiply the denominators so as to obtain one fraction only. You'll get (x - 2)/(2 x3/2)
Then you separate the fraction again to get 1/(2 x1/2) - 1/(x 3/2)
From there its easier to integrate..........try it out.
If you still cannot do it........let me know. :)
-
Your answer is correct :)
-
+rep DK :D
-
Thanks for confirming my answer asif :)
Thank You *Hope* :)
I told you.........you are very encouraging :)
-
Thanks for confirming my answer asif :)
Thank You *Hope* :)
I told you.........you are very encouraging :)
Don't mention it ;)
You really deserve it :)