IGCSE/GCSE/O & A Level/IB/University Student Forum
Qualification => Subject Doubts => GCE AS & A2 Level => Math => Topic started by: thecandydoll on September 18, 2010, 02:48:06 pm
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Paper 1 Pure math !
Summer :May/JUNE 2010
Paper 12.
Question 11,How do solve the whole thing I dont get it :(
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Okay. Hang on.
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(i) 4-3sinx = 2
Hence, 4-2=3sinx I re-arranged the equation
2/3 = sinx
sin-1 2/3 = 41.8, 138.2 degrees
Converting to radians gives: 0.730 and 2.41 respectively.
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(ii) Basically you reflect a regular sine graph in the x axis. Then multiply each Y coordinate by 3.
After that vertically move the graph by 4 units.
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(iii)
Basically they are asking you to find the range of y coordinates for which the Sine Graph has no x values.
Looking at my picture we can see that the graph has no point below the y coordinate of 1 or above the y coordinate of 7.
Hence k > 7 , k < 1
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I dont know the others :P
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Ah we meet again Lioness :P
If a function is to have inverse,it must be one - one function.The graph of such function can only be crossed by a line parallel to the x axis once only .
As our Lioness Ari drew in his Graph the highest value by which the graph is parallel to x axis is 3/2 pi
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Ah we meet again Lioness :P
If a function is to have inverse,it must be one - one function.The graph of such function can only be crossed by a line parallel to the x axis once only .
As our Lioness Ari drew in his Graph the highest value by which the graph is parallel to x axis is 3/2 pi
Subconsciously you know I am a male. Your just a scatter brain. :P
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Sub consciously or consciously I Doubt you are a Lion at all.
Maybe a Cub but thats about it.
Meet the Rogue Lion that will in time kill the heard's leader and finish off the cubs. :-\
I am so Jobless today :-\
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u both can just stop fighting with arguments as ur wepons
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Sub consciously or consciously I Doubt you are a Lion at all.
Maybe a Cub but thats about it.
Meet the Rogue Lion that will in time kill the heard's leader and finish off the cubs. :-\
I am so Jobless today :-\
You sound drunk...
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Here :)
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Give +rep to me yeah.i am dieing to get a rep
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rep r not asked for
they r given if any users want
so dont force them to give +rep
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Give +rep to me yeah.i am dieing to get a rep
Do not ask for rep...against the rules ::)
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I am bored :/
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Find a teacher to give you some homework. ;)
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The answer isn't 0.34
it's 2.80....check the marking scheme (attached)
Why did they say pi-0.34..uh?
How?
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The answer isn't 0.34
it's 2.80....check the marking scheme (attached)
Why did they say pi-0.34..uh?
How?
O thanks for finding my error :D +rep
In the question it says the domain is 0.5pi<x<1.5pi(A).
o.34 is not within this domain so the answer is pi-0.34.
i modified my post :)
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Asif, I need you again. :)
How would I find the inverse of this y= 2x2-12x+13
Thanks :D
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Asif, I need you again. :)
How would I find the inverse of this y= 2x2-12x+13
Thanks :D
Let f(x) = 2x2 - 12x + 13
First you should complete the square of the equation.
You'll obtain f(x) = 2(x-3)2 - 5
To obtain its inverse, you need to make x subject of formula.
Let 2(x-3)2 - 5 = y
y + 5 = 2(x-3)2 ----> (y + 5)/2 = (x-3)2
Now you take roots on both sides.
((y+5)/2)1/2 = x - 3
Hence x = ((y+5)/2)1/2 + 3
Now replace y by x
f-1(x) = ((x+5)/2)1/2 + 3
Therefore the inverse of the given equation will be ((x+5)/2)1/2 + 3
Hope it helps :)
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DK your workings will definitely help ;)........+rep
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DK your workings will definitely help ;)........+rep
Thanks buddy :)