Post by: Galleria on August 30, 2010, 01:34:34 pm
I need something to read from about Bearing. I dont understand it. I mean I understand that it is checked from a clockwise point and all the stuff... but those questions on the past papers need different concepts ? Does anyone have a link to learn Bearing that can help me for IGCSE?
Post by: elemis on August 30, 2010, 01:39:00 pm
Its the same basic concept as in your textbook. However, there are some tricks. ;)
Post by: Dibss on August 30, 2010, 01:57:02 pm
http://www.astarmathsandphysics.com/igcse_maths_notes/igcse_maths_notes_bearings.html
http://www.astarmathsandphysics.com/igcse_maths_notes/igcse_maths_notes_bearings.html~
And then try solving past paper bearing questions to get used to the type of questions.
Post by: Galleria on August 30, 2010, 02:17:20 pm
but i dont understand this
http://www.xtremepapers.net/CIE/Cambridge%20IGCSE/0580%20-%20Mathematics/0580_s08_qp_4.pdf
No 4, b(ii).
Post by: elemis on August 30, 2010, 02:19:56 pm
lol i found that ........... it helped me a little
but i dont understand this
http://www.xtremepapers.net/CIE/Cambridge%20IGCSE/0580%20-%20Mathematics/0580_s08_qp_4.pdf
No 4, b(ii).
One minute.
Post by: Galleria on August 30, 2010, 02:22:26 pm
Post by: elemis on August 30, 2010, 02:26:58 pm
Next for ii find the middle value of each class interval (in blue below).
Multiply the Middle Value to its corresponding frequency :
5 x 12 = 60
15 x 34 = 510
etc.
You see the above values in red ? Add those up to get 7220 and divide it by 200 (just add 12+ 34+ 36+ 30+ 38+ 30+ 16 + 4)
You will get a mean of 36.1 I think.
Is that correct ?
Post by: elemis on August 30, 2010, 02:28:47 pm
oh sorry . that should be s09 . not s08 . :D
Hang on.
Post by: Galleria on August 30, 2010, 02:37:19 pm
Post by: elemis on August 30, 2010, 02:40:41 pm
Post by: elemis on August 30, 2010, 02:44:36 pm
Click on it to enlarge.
Post by: Galleria on August 30, 2010, 02:47:03 pm
Post by: elemis on August 30, 2010, 02:48:13 pm
OMG Like thank you sooooooooooooo much .
Your welcome. :)
Just dont forget the Lion, that's me :P
Any more questions ?
Post by: Galleria on August 30, 2010, 02:52:27 pm
waaaait , ill see if i can do this or not first . then i'll ask the lion ;) . :D
Post by: elemis on August 30, 2010, 02:53:28 pm
looooooooooooooool
waaaait , ill see if i can do this or not first . then i'll ask the lion ;) . :D
I'll be online for another 35 minutes - then I'll come back later on.
Post by: Galleria on August 30, 2010, 03:09:04 pm
but i dont understand something in this question
specially since idk what it is
http://www.xtremepapers.net/CIE/Cambridge%20IGCSE/0580%20-%20Mathematics/0580_s10_qp_42.pdf
No . 5(c) ... :D
Post by: elemis on August 30, 2010, 03:19:25 pm
Post by: elemis on August 30, 2010, 03:23:34 pm
Post by: elemis on August 30, 2010, 03:29:33 pm
Basically they're asking you how far to the left would you need to walk from A to be directly in line with T.
So looking at the compass directions draw a right angled triangle (shown in red) and solve.
I did this paper for my IGCSEs and got and A* so dont sweat it.
Just keep practicing ;)
Post by: Galleria on August 30, 2010, 03:34:01 pm
Post by: elemis on August 30, 2010, 03:45:23 pm
Thaaaaaaaaaaaaaaaaaaaanks!
No worries ;)
Post by: Galleria on August 30, 2010, 04:26:08 pm
:(
im fearing . what should i do ? i'm giving Coordinated Science, Math, English first language, history, English second language and Computer ... lol our school is straaange . but really tough . 3 international exams. igcse's just one :( . + all the mocks for the exams and other normal exaaaams. :(
Post by: elemis on August 30, 2010, 07:18:41 pm
daaaaayum . you're done with your igcse's ? M/J ?
:(
im fearing . what should i do ? i'm giving Coordinated Science, Math, English first language, history, English second language and Computer ... lol our school is straaange . but really tough . 3 international exams. igcse's just one :( . + all the mocks for the exams and other normal exaaaams. :(
Yeah I answered in may/june of this year - physics was a bit tough, I came out alright though :)
The only thing TO DO for IGCSEs are pastpapers and I mean ALL of them. Not just 4 years worth, but all of them.
You've got like a month now, so get your game together and just keep practicing pastpapers - you should have looked at the syllabus and finished your textbook stuff by now.
Good Luck ;)
Post by: Galleria on September 01, 2010, 04:41:04 pm
:O
I have not finished my text book stuff by now . lol . my mock exams are next week and idk anything of math and science . still studying for science . lol 2 months By the way ;) . lol . what should i do ? should i finish studying quickly and be thorough with the boooks ? because they're big . lmao . i'm scared . and oh By the way , i was doing M/J 2010 paper 4 of math . that polygon question , omg what the hell .. there's a formula for finding diagonals ? i didn't even know .
Post by: elemis on September 01, 2010, 05:50:52 pm
You DONT need to know that formula. In the exam I had to prove what the formula was; which I did successfully.
Do you need help with it ?
Study your textbook PROPERLY. Every detail matters.
Past papers are the key.
Start moving fast - time is running out.
Post by: Galleria on September 02, 2010, 11:11:51 am
Post by: elemis on September 02, 2010, 01:34:42 pm
okaaaaaaaaay i think im dead . lol . this M/J 2006 paper is sooooooooooooooooooooooo HARD . Paper 4 . omg . lol . idk what i'm gonna do . my mock exams are next week
Post here if you have problems.
Post by: Galleria on September 02, 2010, 03:58:22 pm
Post by: elemis on September 02, 2010, 03:59:39 pm
okaaay! idk no 2 , 3 and 4. lol :D
Give me a link to the paper please.
Post by: elemis on September 02, 2010, 04:06:26 pm
Post by: elemis on September 02, 2010, 04:29:02 pm
a) Looking at diagram 2 first add up the straight side lengths. 6 + 22 + 18 + 10 = 56
Then find the the arc length of the quarter circle in the top left hand corner. This is done by
b) Looking at diagram 2 again. 10 x 18+ 6 x 12 + 0.25 x pi x 122 = 365 cm2
c) Take the area previously calc. and multiply by the length (40 cm).
d) tomorrow. Have to go now.
Post by: Galleria on September 06, 2010, 01:33:17 pm
do you know physics/chem ?
Can you answer this question generally?
If there are two electrodes connected to a voltmeter and a circuit, then how do we ensure that the gap between them remains equal or how can we measure the gap without putting a ruler inside the beaker ? . lol
Post by: Arthur Bon Zavi on September 06, 2010, 01:39:58 pm
loooool thanks !
do you know physics/chem ?
Can you answer this question generally?
If there are two electrodes connected to a voltmeter and a circuit, then how do we ensure that the gap between them remains equal or how can we measure the gap without putting a ruler inside the beaker ? . lol
By Using Sensors connected to the computer!
Post by: elemis on September 06, 2010, 02:26:55 pm
loooool thanks !
do you know physics/chem ?
Can you answer this question generally?
If there are two electrodes connected to a voltmeter and a circuit, then how do we ensure that the gap between them remains equal or how can we measure the gap without putting a ruler inside the beaker ? . lol
I did Physics and Chem for my IGCSEs ;)
I remember this question - from paper 6, right ?
I wrote separate the electrodes using a block of wood. My teacher said that would be an acceptable answer.
Post by: Arthur Bon Zavi on September 06, 2010, 02:37:41 pm
his result. However he finds that when he tries to do this his hand and the rule prevent
the light reaching the screen. Suggest briefly a method he could use to measure the
height of the image on the screen that would overcome this problem.
AND This Was the Answer as on the marksheet:
scale drawn on paper on screen/graph paper on screen/
mark on screen (then) measure/clamp ruler on scale/
use translucent screen and measure from other side :o
;D ;D ;D
Post by: Galleria on September 06, 2010, 03:33:19 pm
and lool thanks! @ Ari . But it was for some other year lol . hmm but then how would the electrodes remain steady ? i mean they could move and stuff
Post by: elemis on September 06, 2010, 03:36:46 pm
@ the only one .. that's not it -___-
and lool thanks! @ Ari . But it was for some other year lol . hmm but then how would the electrodes remain steady ? i mean they could move and stuff
Does this answer your question ?
Post by: elemis on September 06, 2010, 03:38:33 pm
By the way, the grey rectangles are the electrodes ;)
Post by: elemis on September 06, 2010, 03:41:32 pm
Post by: Galleria on September 06, 2010, 04:37:56 pm
Post by: elemis on September 07, 2010, 10:03:37 am
Thank you sooooooo much! Are you doing your A Levels or something ? lol
Yeah, I just started my AS Levels.
Post by: Galleria on September 08, 2010, 01:33:00 pm
Post by: astarmathsandphysics on September 08, 2010, 01:48:29 pm
Post by: Galleria on September 08, 2010, 01:54:25 pm
Post by: Galleria on September 08, 2010, 01:58:30 pm
http://www.xtremepapers.net/CIE/Cambridge%20O%20Levels/5124%20-%20Science%20(Physics,%20Chemistry)/5124_w03_qp_3.pdf - Question 5
http://www.xtremepapers.net/CIE/Cambridge%20O%20Levels/5124%20-%20Science%20(Physics,%20Chemistry)/5124_w05_qp_3.pdf - Question 6
http://www.xtremepapers.net/CIE/Cambridge%20O%20Levels/5124%20-%20Science%20(Physics,%20Chemistry)/5124_w07_qp_2.pdf - Q 8 and 9
I just need to know the correct answers ... there are no mark schemes :(
I know they're O level questions but it's our homework ... marked out of 10 . i'm giving my igcse's.
Post by: elemis on September 08, 2010, 04:36:15 pm
3 (a) (i) I'm sure you're capable of drawing this ;)
(ii) Add bromine water - with E the bromine water remains orange in colour. With F it is decolourised.
(iii) 12 *2 + 6 = 30
b) i) It has C double bonds.
ii) Its Polyethen - look it up in your textbook
iii) creates visual pollution - eyesores
releases toxic gases like hydrogen cyanide.
Post by: elemis on September 08, 2010, 04:44:30 pm
(a) (i) Hydrogen
water vapour
ii) beium,ceium,deium
(b) i) copper
(ii) current ore deposits are being used up at an ever faster rate and as these metal ores are non-renewable we may have to look to other sources in the future.
Post by: elemis on September 08, 2010, 04:48:38 pm
a) F J
b) I
c) I H
d) H
Post by: elemis on September 08, 2010, 04:57:16 pm
90/60 = 1.5 A
1.5 * (4*8/(4+8)) = 4 V is the PD across each resistor. Hence, 4/8 = 0.5 A (use the equation V=IR)
4V (see above)
The 4 ohm resistor transfer more energy per second. Use the equation E = V*I*t to prove this.
the earth comes into operation if a live wire touches the exposed part of the case this causes a large current to flow hence causing the fuse blow and preventing further flow of current.
Post by: Galleria on September 08, 2010, 05:41:39 pm
THANK YOU SO MUCH!
:D:D:D:D:D:D:D:D
You rooock! . They should +100 rep you . lol
Post by: elemis on September 09, 2010, 05:49:51 am
You Might as well +rep me if you feel I've done a good job :P
Post by: Galleria on September 27, 2010, 03:52:59 pm
Post by: elemis on September 27, 2010, 04:00:59 pm
It lists all useful resources and websites for all A Level Sciences :
https://studentforums.biz/reference-material-83/ultimate-resource-guide-for-a-level-bio-chem-and-phy-!!/ (https://studentforums.biz/reference-material-83/ultimate-resource-guide-for-a-level-bio-chem-and-phy-!!/)