IGCSE/GCSE/O & A Level/IB/University Student Forum
Qualification => Subject Doubts => IB => Math => Topic started by: Matricaria on October 15, 2011, 12:26:32 pm
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Find Modulus and Argument of X^4=1?
I used De Moivre's Theorem and to find the four roots which are: 1, -1, i, and -i..
I also plotted the argand diagram but can't calculate r and theta since all four points are on the axes...
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r=1 and therapy=0,pi,pi/2 and 3pi/2 respectively
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O, thanks :)
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r=1 and therapy=0,pi,pi/2 and 3pi/2 respectively
One last thing:
This is the problem:
- Use de moivre's theorem to obtain solutions for z^3-1=0
- Use graphing software to plot these roots on an argand diagram as well as a unit circle with centre origin.
- Choose a root and draw line segments from this root to the other two roots.
- Measure these line segments and comment on your results.
- Repeat the above for the quations z^4-1=0 and z^5-1=0. Comment on you results and try to formulate a conjecture.
So I worked out the roots for z^3, z^4, and z^5 using de Moivre's
for z^3: 1, -1/2 + i*sqrt(3/2), -1/2 - i*sqrt(3/2)
for z^4: 1, -1, i, and -i
for z^5: 1, cos(2pi/5) + isin(2pi/5), cos(4pi/5) + isin(4pi/5), cos(6pi/5) + isin(6pi/5), and cos(8pi/5) + isin(8pi/5)
I also plotted the roots for all three equations on an argand diagram and a unit circle and my observation was that any root for z^n=1 will lie an the unit circle and that all roots of z^n=1 are equally spaced around the circle..
Then I calculated the distance between each two roots to find out the following:
For z^3: sqrt3
For z^4: sqrt2
For z^5: Approx value 1.175570505
Then I tried to formulate a general equation for the distance between any two neighboring roots of z^n=1, and I came up with this:
|cis2pi/n - 1|
NOW: My findings are:
z^n=1 has n roots given by z=cis(k 2pi/n), where k is the number 0, 1, ..., n-1.
The distance between 2 neighboring roots is |cis2pi/n - 1|.
However, I'm afraid this is not a conjecture, but just fact...
Can you please tell me how to put these findings into a conjecture?????????????
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Looks like a proper investigation. Will do it in bed in morning.
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Thank you very much.. Your help's appreciated..
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see attachment for distance between roots
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Oh!
So my distance formula was wrong!
Thank you very much, one last thing, though: How do I put these findings into a conjecture??
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work out the distance for first principles with n=3,4,5 then 'notice x=2sin (2pi/n)