Hello,
Please see the question below, attachment.
answer to b) i) is
q-p
I did this like this PQ = OQ - OP (position vectors)
next part ii) This is my concern
I do it like this,
OX = PX - PO (position vectors)
so, it gets like this :
= q-p/3 - q
= q-p-3q/3
= -2q-p/3 (answer)
but on mark scheme, the answer is 2q+p/3
Whats wrong? and Whats weak in my concept of vectors, can any one please clear it?The question is of M/J 2004 O Level Paper 02 Math 4024.
Dear Ricky, you actually did everything correctly... :) However, when you came to 'OX=PX-PO', I think that you accidentally substituted 'q' into 'PO' instead of 'p'. If you do this, you will get the answer...
To Darsith, I'm thinking that maybe you did something wrong in your calculations along the way, and forgot about the denominator of 3. I hope that I helped. :)
Dear Ricky, you actually did everything correctly... :) However, when you came to 'OX=PX-PO', I think that you accidentally substituted 'q' into 'PO' instead of 'p'. If you do this, you will get the answer...
To Darsith, I'm thinking that maybe you did something wrong in your calculations along the way, and forgot about the denominator of 3. I hope that I helped. :)
Hi Dasith, sorry for the late reply... >< I was a little tied up with my exams...
I shall include my working for the second part of the question here, the one on finding OX:
OX=OP+PX
=p + 1/3(-p+q)
=p - 1/3p+ 1/3q
=2/3p + 1/3q
When I saw that Ricky said that the answer is '1/3(2q+p)' , I was stumped as it was different from the answer I got above. However, I checked the answer scheme, which said that my answer is correct. It's actually '1/3(2p+q)... Do you see any difference between your working and mine? :) Do let me know if you have any further difficulties...
Hmm, are you trying to say that my method is quite long-winded?? :-[ Heheh, I get that a lot... I guess that the A level course that I am currently taking is getting to my head! XD 8)
Anyway, you were right about the answer to b(i) posted by Ricky being wrong... I missed that earlier. And yes, your method also gets the same answer of 2/3p+1/3q... but isn't it almost the same as my method? Hmm... I mean that isn't 'p + 1/3(-p+q)' the same as p +(-p+q)/3 :o
Ermm, do you understand what I'm trying to say? :-\
:D Oh, okay, that's settled then, I guess! It was quite an interesting question, I suppose... I hope that Ricky managed to read this in time for any exams he might have. ;D