IGCSE/GCSE/O & A Level/IB/University Student Forum
Qualification => Subject Doubts => IGCSE/ GCSE => Sciences => Topic started by: Q80BOY on May 02, 2009, 05:28:31 pm
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Hey guys,
I need help with the following questions
(1) Physics P6 May/June 2007
Q3 Part (b) and (c) (**DONE**)
(2) Physics P6 October/November 2006
Q1 Part (c) (**DONE**)
[b]Q3[/b] Part (b) (**DONE**)
(3) Physics P6 May/June 2006
Q1 Part (d) <-- i didnt understand ur answer astar plz help ! :'(
Q3 Part (a) Section (v) and (vi) (**DONE**)
Q5 Part (a) (**DONE**)
Thanks a lot for your help !!
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Astar your help is needed over here
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Physics P6 May/June 2007
Q3 Part (b)(c) The answer is R is proportional to 1/d2 because when you double the diameter the resistance is decreased by 4 times. The diameter is inversely proportional to d (check the values of the resistance you calculated in the table and see whether the answer to wire AB is 4 times the answer to CD)
(2) Physics P6 October/November 2006
Q3 Part (b) (i)You should place 2 pins on the incident ray (GJ) and 2 pins on the reflected ray (GK). You have already found the position of pin A previously. Make sure that the gap between the pins on the same ray are atleast further apart than 5 cm (the theory to this complicated and you don't really need to know it).
(ii) You would view the bases because it is easiest to view if the pins are standing upright or not.
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Which board is this for? I am sure it is not CIE.
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well from whats written it looks like cie paper 6 alternative to coursework
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I cant find any paper 6s for CIE Physics A Level. Which board is it?
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Its IGCSE not A level right?
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I cant find the papers. Can you post links on freeexampapers or upload the papers here?
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It's IGCSE and the board is CIE.
Thanks a lot for the help godfather93
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Another site of past papers
pastpapers4free.weebly.com/igcse.html
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Hey guys,
I need help with the following questions
(1) Physics P6 May/June 2007
Q3 Part (b) and (c)
(2) Physics P6 October/November 2006
Q1 Part (c)
Q3 Part (b)
(3) Physics P6 May/June 2006
Q1 Part (d)
Q3 Part (a) Section (v) and (vi)
Q5 Part (a)
Thanks a lot for your help !!
(1) Physics P6 May/June 2007
Q3 Part (b) and (c)
R is proportional to 1/d2
When we times the diamter by 2 we divide the resistance by 22
Draw 2 lamps and a voltmeter all in paralell and an ammeter in series.
(2) Physics P6 October/November 2006
Q1 Part (c)
Q3 Part (b)
V=7.64 taking l as 4.
for the actual volume of the rods you have two guess what fraction is air. I guessed 10% then d=m/V=6.3/7.64=0.82g/cm3
Put the pins as far from each other as possible. Line your eye up with the base, since the pins may lean over.
I have to go and teach some maths now. Back in a few hours to answer the other question.
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Thanks astar !! ;D
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I added some more questions
(4) Physics P6 October/November 2005
Q2 Part (a) <-- i put the resistors AB and BC in sereis, and resistor CD in parallel, i put the voltmeter in parallel (under CD) am i right ?? Plz help !! :'(
(5) Physics P6 May/June 2005
Q3 Part (e) (**DONE**)
I really apreciate ur help guys !!
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I added some more questions
(4) Physics P6 October/November 2005
Q2 Part (a)
(5) Physics P6 May/June 2005
Q3 Part (e)
I really apreciate ur help guys !!
(4) Physics P6 October/November 2005
Q2 Part (a)
Difficult to do with a sketchb but draw the same diagram with a box on each connecting wire and another between A and D with a box.
(5) Physics P6 May/June 2005
Q3 Part (e)
r=0.95/0.375 FOR aB length 0.5m. If you triple the length to 1.5m you triple the resistance to 3(0.95/0.375)
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Thanks astar, can u plz help me with the may/june 2006 (questions are at the top)
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Hey guys,
I need help with the following questions
(1) Physics P6 May/June 2007
Q3 Part (b) and (c)
(2) Physics P6 October/November 2006
Q1 Part (c)
Q3 Part (b)
(3) Physics P6 May/June 2006
Q1 Part (d)
Q3 Part (a) Section (v) and (vi)
Q5 Part (a)
Thanks a lot for your help !!
Q1 Part (d)
Q3 Part (a) Section (v) and (vi)
Q5 Part (a)
1d)lx*w*2.5 where l and w are your answers from b)
a)v)Measure HF with a compass then use that mesuremnent to draw the line.FI
vi)
From I Draw part of a large circle that cuts NN' in two place. Find the half waypoint between these 2 with a ruler and call it K then draw the line KI.
5a) Measure the height of the 2 ends of the ruler above the bench with another ruler.
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Hey guys,
I need help with the following questions
(1) Physics P6 May/June 2007
Q3 Part (b) and (c)
(2) Physics P6 October/November 2006
Q1 Part (c)
Q3 Part (b)
(3) Physics P6 May/June 2006
Q1 Part (d)
Q3 Part (a) Section (v) and (vi)
Q5 Part (a)
Thanks a lot for your help !!
Q1 Part (d)
Q3 Part (a) Section (v) and (vi)
Q5 Part (a)
1d)lx*w*2.5 where l and w are your answers from b)
a)v)Measure HF with a compass then use that mesuremnent to draw the line.FI
vi)
From I Draw part of a large circle that cuts NN' in two place. Find the half waypoint between these 2 with a ruler and call it K then draw the line KI.
5a) Measure the height of the 2 ends of the ruler above the bench with another ruler.
What do u mean by part of a large circle ?? a semi circle ?? im confused ???
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Put your compass point at I and draw part or a large circle with centre at I so it crosses NN' in 2 places.
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it only crosses NN' in one place ???
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The circle will cross NN' in 2 places then find the halfway point between the 2 with a ruler.
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Extend NN' if you have to.
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i finally figured it out, thanks for ur help !! :)
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I have some more questions :D
(6) Physics P6 October/November 2004
Q1 Part (b) section (ii) <-- by circumference, do they mean 2 x pie x radius ?? cause i did it and it didnt work (***DONE***)
(7) Physics P6 October/November 2003
Q1 Part (b) section (i) <-- where do i place the two blocks (the exact location will be verrry helpful)
Q2 Part (a) and (b) <-- where do i draw the incident ray and where do i draw the reflected ray ??
(***DONE***)
i appreciate ur help :)
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CIE or Edexel ??
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CIE or Edexel ??
CIE
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come on guys,
i need help, the exam is after 1 week !!
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:P circumference of a circle =2?r, so the answer of b(i)=75cm in diameter. but they want the radius to calculate the answer. half of 75 which is 37.5. C=2?(37.5)=236cm
I hope i am right :P
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ok the ? means pie, i tried typing the symbol but it dosent work :P so ?=pie
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:P circumference of a circle =2?r, so the answer of b(i)=75cm in diameter. but they want the radius to calculate the answer. half of 75 which is 37.5. C=2?(37.5)=236cm
I hope i am right :P
are u sure ?? the mark scheme says 15 cm ???
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screw them >:] i am right :P. the other thing that i did but i know its not correct is 75cm the diameter divided by the number of turns which is 5 :P see how smart i am in physics xP
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screw them >:] i am right :P. the other thing that i did but i know its not correct is 75cm the diameter divided by the number of turns which is 15 :P see how smart i am in physics xP
lol ;D so whats the right answer ?? 15 or 236 ?
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its 15 .. length / number of turns = 75/5 = 15 ans
i did the Q 2 parts too ,, mm my scanner isnt working or i wud have scanned it for u
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its 15 .. length / number of turns = 75/5 = 15 ans
i did the Q 2 parts too ,, mm my scanner isnt working or i wud have scanned it for u
Thanks emi, appreciate ur help !! :)
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Q2) part a) and b) - O/N 2003-
here is how it looks like .. just measure the points they want
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can nyone ov u plz tell me wat da hek wil b its ans....
oct/nov 2006 part c (i)....
in details plzzz.... its really very confusing.. wat i did is i applied a formula v=l*a i.e: volume=length*area..
plz ppl try to solve it n help me...ill b grate ful 2 u :D
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they give you the formula V=c2l/4pi
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Q2) part a) and b) - O/N 2003-
here is how it looks like .. just measure the points they want
now thats what i call help !!! thanks a lot ;D
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PENDING QUESTIONS (Level: IGCSE, Board: CIE)
(3) Physics P6 May/June 2006
Q1 Part (d) <-- i didnt understand ur answer astar, plz help !!
(4) Physics P6 October/November 2005
Q2 Part (a) <-- i put the resistors AB and BC in series, and reisitor CD in parallel. i put the voltmeter in parallel (under CD) am i right ??? plz help !!
(7) Physics P6 October/November 2003
Q1 Part (b) section (i) <-- where do i place the two blocks ?? (the exact location will be verrry helpful) (***DONE***)
NEW QUESTION
( 8 ) Physics P6 May/June 2003
Q2 Part (b) section (i) and (ii) (***DONE***)
Thanks a lot !!! :D
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hey Qboy have you sent the chem papers?? I sent the correct email adress to your email!
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hey Qboy have you sent the chem papers?? I sent the correct email adress to your email!
i sent them, check ur inbox ;)
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hey
I'll answer ur new question
the question is
1)(b) The angle of refraction as the ray entered side AB of the prism was 22°.
(i) On Fig. 2.1, draw in the refracted ray from point D as accurately as possible.
You just need to draw the angle 22° from point D..
(ii) Mark the point E, where the ray meets side AC. Draw the normal at point E.
My scanner is not working so used paint
Hope u understand from my explanation
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Thanks for the gr8 help IG girl + REP ;D
1 question though, what do they mean by draw the normal at point E ? i just draw a straight line ?
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Thanks for the gr8 help IG girl + REP ;D
1 question though, what do they mean by draw the normal at point E ? i just draw a straight line ?
U welcome
U just need to draw a straight line...it's as simple as that ;)
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thanks a lot, ur a life saver ;D
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NEW QUESTION (Level: IGCSE, Board: CIE)
(9) Physics P6 May/June 2002
Q3 Part (c) section (iii) <-- i did 24 divided by 330 = 0.072727273, the m/s says the answer is in the range of 2.5 - 3.0 ???
Q4 Part (a) section (iv) <-- i didnt understand what they actually want from me !! plz help
Thanks a lot :)
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i need ur help guys !!! :'( pleeeeeeeeeese !!
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NEW QUESTION (Level: IGCSE, Board: CIE)
(9) Physics P6 May/June 2002
Q3 Part (c) section (iii) <-- i did 24 divided by 330 = 0.072727273, the m/s says the answer is in the range of 2.5 - 3.0 ???
Q4 Part (a) section (iv) <-- i didnt understand what they actually want from me !! plz help
Thanks a lot :)
For Sc, use the previous answers both about 3
For 4aiv) Draw the line ABmirror P and the line DCmirror, now from the mirror draw a line paralell to mirrorP
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hi do u hv physics past year papers from 1993-2003??
i am really not that gud in physics :(
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Q3. <-- what do i do with the previous answers ?? (add, multiply, divide ??) (***DONE***)
Q4. <-- can u show me a diagram or something ??? (i attached a scan of my paper, what should i do next) (***DONE***)
plz i really need the help !!!
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hi do u hv physics past year papers from 1993-2003??
i am really not that gud in physics :(
no i dont, sorry :-[
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ok thankx...
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help !! anyone ?? :'(
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hey do still need help for that question u scanned cos i think i got the ans. :)
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hey do still need help for that question u scanned cos i think i got the ans. :)
ya sure, plz !! :)
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ok lets see....
1st: draw the line C to D until it touches the mirror
2nd:draw the line A to B until it touches the mirror
3rd: extend the lines CD and AB to the back of the mirror until they intersect
4th: the point of intersection(at the back of the mirror) is the place where the image position I is gonna be.
thats it :)
therefore it is virtual because the lines intersect behind the mirror
if it intersected in front of the mirror, then it is real...
do u get it??
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ok lets see....
1st: draw the line C to D until it touches the mirror
2nd:draw the line A to B until it touches the mirror
3rd: extend the lines CD and AB to the back of the mirror until they intersect
4th: the point of intersection(at the back of the mirror) is the place where the image position I is gonna be.
thats it :)
therefore it is virtual because the lines intersect behind the mirror
if it intersected in front of the mirror, then it is real...
do u get it??
ya i got it ;D Thanks a lot for the help !!!
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hey your Fig.4.2 is absolutely ryt...acatully in my case i made the arrows in the opposite direction...lolz
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hey your Fig.4.2 is absolutely ryt...acatully in my case i made the arrows in the opposite direction...lolz
lol ;) can u help with the other questions ??
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may/jun 2002
Q3 ciii> follow the pattern of the previous answers(ratios are decreasing) and predict the approximate ratio of the next one
Q4 aiv> extend the two rays AB and CD backwards untill they intersect,point I
positionI must be directly above P
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may/jun 2002
Q3 ciii> follow the pattern of the previous answers(ratios are decreasing) and predict the approximate ratio of the next one
Q4 aiv> extend the two rays AB and CD backwards untill they intersect,point I
positionI must be directly above P
Thanks for the help
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on the scanned image u drew on Fig 4.1 one too .. do we have to draw there ? they mentioned Fig 4.2
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on the scanned image u drew on Fig 4.1 one too .. do we have to draw there ? they mentioned Fig 4.2
no we dont, i didnt read the question and thought we should draw on fig. 4.1
sorry for the confusion :-[
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no its ok ,, just thought i was missing some thing ;)
your posting of Questions helps me alot too .. thanks
=D
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no its ok ,, just thought i was missing some thing ;)
your posting of Questions helps me alot too .. thanks
=D
ur welcome ;D
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hi....
im doin my IGCSE phy paper on may 12....please cud u giv me sum paprs to practice??...
my email id is...smack_kooldude12@yahoo.com
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go to www.freeexampapers.com
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I have some more questions :D
(6) Physics P6 October/November 2004
Q1 Part (b) section (ii) <-- by circumference, do they mean 2 x pie x radius ?? cause i did it and it didnt work (***DONE***)
(7) Physics P6 October/November 2003
Q1 Part (b) section (i) <-- where do i place the two blocks (the exact location will be verrry helpful)
Q2 Part (a) and (b) <-- where do i draw the incident ray and where do i draw the reflected ray ??
(***DONE***)
i appreciate ur help :)
at the beginning of the tube and the end of the tube , the blocks SHOULD touch the test tube ..... hope that helps if it doesnt then ill try to do the drawing and put it up
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I have some more questions :D
(6) Physics P6 October/November 2004
Q1 Part (b) section (ii) <-- by circumference, do they mean 2 x pie x radius ?? cause i did it and it didnt work (***DONE***)
(7) Physics P6 October/November 2003
Q1 Part (b) section (i) <-- where do i place the two blocks (the exact location will be verrry helpful)
Q2 Part (a) and (b) <-- where do i draw the incident ray and where do i draw the reflected ray ??
(***DONE***)
i appreciate ur help :)
at the beginning of the tube and the end of the tube , the blocks SHOULD touch the test tube ..... hope that helps if it doesnt then ill try to do the drawing and put it up
Thanks a lot !!! ;D
I added my paper (is it right ??)
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Guys really need help in physics p6 I mean im like lost! most of qs dont make sense!
for eg in 2001nov
1b how do you measure that ??
3b dont you place the weights closer to the pivot moment=force*distance from fulcrum?
but ms says place the 100 g further! huh?
4a(ii) i thought the two precations would be :
1.use same size beaker
2.use same volume of water
but ms not even mentions the sencond which i rote and says that sam intial temperature is apoint. HUH !!!! isnt that already mentioned??
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no Q80 its not like that .. u should put one block at each end of the tube
something like this
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Physics P6 October/November 2005
Q2 Part (a) <-- i put the resistors AB and BC in series, and reisitor CD in parallel. i put the voltmeter in parallel (under CD) am i right plz help !! (***DONE***)
attached diagram below is wrong
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no Q80 its not like that .. u should put one block at each end of the tube
so one block on the test tube, and one block under the test tube ?? and where do i place them, left or right hand side ??
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i attached the image check it out
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mmm i dont know that Question too .. i hope some one could answer you that so we would get helped too
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i attached the image check it out
appreciate ur help, Thanks ;D
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oct/nov 2005
Q2 a> the voltmeter must be connected across the two resistors in series
from A to the first C
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oct/nov 2005
Q2 a> the voltmeter must be connected across the two resistors in series
from A to the first C
Like that ?? (see attachment)
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No move the voltmeter to the resistor CD and add another wire for the resistor you have moved.
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no
i have attached the correct one.
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no
i have attached the correct one.
Thanks a lot ;D +rep
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Guys really need help in physics p6 I mean im like lost! most of qs dont make sense!
for eg in 2001nov
1b how do you measure that ??
3b dont you place the weights closer to the pivot moment=force*distance from fulcrum?
but ms says place the 100 g further! huh?
4a(ii) i thought the two precations would be :
1.use same size beaker
2.use same volume of water
but ms not even mentions the sencond which i rote and says that sam intial temperature is apoint. HUH !!!! isnt that already mentioned??
i attached my answers to (1b) and (3b) but im not sure if theyr'e right ( can someone please confirm)
"same size beaker" is similar to "same volume of water" according to my physics teacher (i cant explain why :P)
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1b) The rule should be vertical at the centre where the load is.
3b) The 55.5 g mass should be about 4.5 divisions from the centre.
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hy qboy thanks mans for atleast repnding to my q!! anyway how come the fulcrum q is like that? since its 100g shouldnt it be closer to the fulcrum?? and also they q before how ccan u fin length of drepression from taht?
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1b) The rule should be vertical at the centre where the load is.
3b) The 55.5 g mass should be about 4.5 divisions from the centre.
a diagram would be very helpful, or a further explanation :D
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hy qboy thanks mans for atleast repnding to my q!! anyway how come the fulcrum q is like that? since its 100g shouldnt it be closer to the fulcrum?? and also they q before how ccan u fin length of drepression from taht?
didnt understand ur first question :-[
length of depression was found by the graph (see attachment) the answer is 28.5 d/mm :)
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When you measure the depression you measure the vertical displacement from equilibrium. This is done with a vertical ruler in the middle of the rod.
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i was talking about the 3b question. should the 100 g placed closer to fulcrum to balance the fuclrum as
A.C.M=C.M
so 100*x=55.5 * 20
thus x=(55.5*20)/100=11.1 cm
so the 100g must be placed at like 1 division right?
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SHOOT ME!!!!! \N QGHTBV
SHOOT ME AGAIN!!!!!!
You are right I thought the 100g and 55g mass were the other way round.
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I think that one should look like this
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so where should the 100g be placed ?
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11.1CM FROM THEcentre.
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astar u answer is what it says in the q but i dont know how. Please can ou loka t question and help me? thanks again idk how i could have survived otherwise
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astar ur first ans is wat the ms said was correct
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I think that one should look like this
r u sure ?? i have 3 different answers now ???
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11.1CM FROM THEcentre.
how ?? the whole diagram is 9 cm only ???
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qboy he said from centre and no the whole thing is not 9cm its 100cm checkq and any the ms say the ottherway around why????
mass on correct side [1]
approx twice as far from pivot (by eye) [1]
(between 35 and 40)
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55.5*20=100*x so x= 1110/100=11.1 and this is the correct answer.
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so ms is wrong?
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55.5*20=100*x so x= 1110/100=11.1 and this is the correct answer.
is this right ?? (see attachment) ???
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MY QUESTION is why does the ms say otherwise? AHHH TO MUCH TO STDY!!
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Does the ms say from the edge or the centre? I say from the centre.
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Does the ms say from the edge or the centre? I say from the centre.
it says
mass in correct side [1]
approx twice as far from pivot (bye eye) [1]
(between 35 and 40)
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In that case I think the ms is wrong.
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can someone tell me which question u guys are discussing so i can help out
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Cot/Nov 2001 P6 Q3b
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well this is wat i think
clockwise = anti clockwise
55.5 X 20 = 100x
x= 11.1 cm
now take a ratio
actual : map
25 cm : 4.3 cm
11.1 cm : X
x = 1.9
hence from the pivot draw 1.9 cm box of mass
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well this is wat i think
clockwise = anti clockwise
55.5 X 20 = 100x
x= 11.1 cm
now take a ratio
actual : map
25 cm : 4.3 cm
11.1 cm : X
x = 1.9
hence from the pivot draw 1.9 cm box of mass
Thanks for the gr8 help ;D
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anytime :D glad i helped u :D ;D !!