IGCSE/GCSE/O & A Level/IB/University Student Forum

Qualification => Others => GCSE => Topic started by: astarmathsandphysics on September 21, 2009, 09:52:22 am

Title: Latest gcse maths notes at astarmathsandphysics.com
Post by: astarmathsandphysics on September 21, 2009, 09:52:22 am

I think I solved the picture problem and now the pages display properly.

http://www.astarmathsandphysics.com/gcse_maths_notes/gcse_maths_notes_pythagoras_theorem.html

Title: Re: Latest gcse maths notes at astarmathsandphysics.com
Post by: astarmathsandphysics on September 25, 2009, 08:17:22 pm

http://www.astarmathsandphysics.com/gcse_maths_notes/gcse_maths_notes_factorising_into_two_brackets_when_the_leading_term_is_x2.html
http://www.astarmathsandphysics.com/gcse_maths_notes/gcse_maths_notes_factorising_simple_expressions.html

Title: Re: Latest gcse maths notes at astarmathsandphysics.com
Post by: astarmathsandphysics on September 26, 2009, 11:17:42 pm

http://www.astarmathsandphysics.com/gcse_maths_notes/gcse_maths_notes_cosine_rule.html

http://www.astarmathsandphysics.com/gcse_maths_notes/gcse_maths_notes_sine_rule.html

http://www.astarmathsandphysics.com/gcse_maths_notes/gcse_maths_notes_trigonometry_and_right_angled_triangles_finding_an_angle.html

http://www.astarmathsandphysics.com/gcse_maths_notes/gcse_maths_notes_trigonometry_and_right_angled_triangles_finding_a_side.html

Title: Re: Latest gcse maths notes at astarmathsandphysics.com
Post by: astarmathsandphysics on September 27, 2009, 08:21:48 pm

http://www.astarmathsandphysics.com/gcse_maths_notes/gcse_maths_notes_trial_and_improvement.html
http://www.astarmathsandphysics.com/gcse_maths_notes/gcse_maths_notes_direct_and_inverse_proportion.html

Title: Re: Latest gcse maths notes at astarmathsandphysics.com
Post by: astarmathsandphysics on September 28, 2009, 11:38:49 pm

http://www.astarmathsandphysics.com/gcse_maths_notes/gcse_maths_notes_circle_theorems_a_summary.html

http://www.astarmathsandphysics.com/gcse_maths_notes/gcse_maths_notes_estimating_and_approximation.html

http://www.astarmathsandphysics.com/gcse_maths_notes/gcse_maths_notes_finding_the_rules_or_nth_terms_for_quadratic_sequences.html

http://www.astarmathsandphysics.com/gcse_maths_notes/gcse_maths_notes_finding_the_rules_or_nth_terms_for_simple_sequences.html

http://www.astarmathsandphysics.com/gcse_maths_notes/gcse_maths_notes_gradients_and_equations_of_lines.html

http://www.astarmathsandphysics.com/gcse_maths_notes/gcse_maths_notes_simplifying_surds.html

Title: Re: Latest gcse maths notes at astarmathsandphysics.com
Post by: astarmathsandphysics on September 29, 2009, 10:55:06 pm

Finding
the Mean of a Frequency Table (http://www.astarmathsandphysics.com/gcse_maths_notes/gcse_maths_notes_finding_the_mean_from_a_frequency_table.htmll)Finding
the Highest Common Factor (HCF) of Two Numbers (http://www.astarmathsandphysics.com/gcse_maths_notes/gcse_maths_notes_finding_the_highest_common_factor_of_two_numbers.html)Mode,
Median and Mean (http://www.astarmathsandphysics.com/gcse_maths_notes/gcse_maths_notes_mode_median_mean.html)Standard
Form (http://www.astarmathsandphysics.com/gcse_maths_notes/gcse_maths_notes_standard_form.html)Percentages,
Fractions and Decimals (http://www.astarmathsandphysics.com/gcse_maths_notes/gcse_maths_notes_percentages_fractions_and_decimals.html)Finding
the Lowest Common Multiple of Two Numbers (http://www.astarmathsandphysics.com/gcse_maths_notes/gcse_maths_notes_lowest_common_multiple.html)

Title: Re: Latest gcse maths notes at astarmathsandphysics.com
Post by: sweetest angel on October 06, 2009, 09:57:05 pm

hey,Thanks for the links but i have a problem in logs that i'll be very grateful if u solve
i'll use ^ to indicat a number power
Q: prove that if a^x=b^y=(ab)^xy, then x+y=1
this is a question from C2 AS edexcel. thanks a lot in advance  :D

Title: Re: Latest gcse maths notes at astarmathsandphysics.com
Post by: astarmathsandphysics on October 06, 2009, 11:10:45 pm

a^x=b^y=(ab)^xy, then x+y=1
a^x=a^(xy)b^(xy) take the xth root to get a=a^yb^y (1)
and the the yth root of b^y=a^(xy)b^(xy) to get b=a^xb^x (2)
a^(1-y)=b^y from (1) and b=a^(1-y)/y from (1)
sub into (2) to get a^(1-y)/y=a^xa^x(1-y)/y
hence (1-y)/y=x+x(1-y)/y
1-y=xy+x-xy so 1=x+y

tricky question

Title: Re: Latest gcse maths notes at astarmathsandphysics.com
Post by: astarmathsandphysics on October 06, 2009, 11:11:25 pm

definitely in the wrong topic too.