Author Topic: Physics help!  (Read 11869 times)

Offline @d!_†oX!©

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Re: Physics help!
« Reply #60 on: August 24, 2010, 05:47:11 pm »
I saw the book too. Pg. 107. What does the markscheme say?

Right, page 107 it is. I don't have the mark scheme, nor do I know which year is this question from. I got this in the "topic-wise mcq"file i downloaded.
AAL IZZ WELL!!! ;)

Offline @d!_†oX!©

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Re: Physics help!
« Reply #61 on: August 24, 2010, 05:48:45 pm »
In a couple the magnitude of the force is the same.


Oh I think I get it now..
AAL IZZ WELL!!! ;)

Offline Saladin

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Re: Physics help!
« Reply #62 on: August 24, 2010, 05:49:38 pm »
It has to be C, there is no other conclusion, the answer fits perfectly....

Offline @d!_†oX!©

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Re: Physics help!
« Reply #63 on: August 24, 2010, 05:50:17 pm »
Oh yes now know..sh*t!
what bloody say mistake I was doing...!!!

Thanks for your time Vin, Engraved and Captain Nid! :D
AAL IZZ WELL!!! ;)

Offline Vin

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Re: Physics help!
« Reply #64 on: August 24, 2010, 05:51:29 pm »
Right, page 107 it is. I don't have the mark scheme, nor do I know which year is this question from. I got this in the "topic-wise mcq"file i downloaded.

Oh OK. Would you mind uploading the file here? :) Thanks. :)

Oh, no probs.

Offline @d!_†oX!©

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Re: Physics help!
« Reply #65 on: August 24, 2010, 05:54:40 pm »
AAL IZZ WELL!!! ;)

Offline Vin

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Re: Physics help!
« Reply #66 on: August 24, 2010, 05:56:50 pm »
Oh sure, here it is. I got it from the link here:
https://studentforums.biz/reference-material-83/asa-level-physics-paper-1-topic-based/msg333437/#msg333437

Thank you for sharing! :) Though I've done very little out of the lot.

nid404

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Re: Physics help!
« Reply #67 on: August 25, 2010, 03:37:08 pm »
Paper 4 Nov 08 Q3)b)ii)

Thanks  :)

nid404

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Re: Physics help!
« Reply #68 on: August 26, 2010, 07:13:38 am »
Anyone?  :-\

Offline Saladin

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Re: Physics help!
« Reply #69 on: August 26, 2010, 12:15:13 pm »
At time 0, there would be 0 displacement, so therefore, the needle would stay in it's original position meaning that it would stay as on the diagram. Basically meaning a maximum or minimum point because it goes from a max to a min. The machine does not start on the piece of cloth.

If displacement is 0, then it has to be in its original position.


nid404

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Re: Physics help!
« Reply #70 on: August 26, 2010, 01:59:38 pm »
At time 0, there would be 0 displacement, so therefore, the needle would stay in it's original position meaning that it would stay as on the diagram. Basically meaning a maximum or minimum point because it goes from a max to a min. The machine does not start on the piece of cloth.

If displacement is 0, then it has to be in its original position.



Yup I got that. I asked for part b) The value of a is 11 :S Shouldn't it be 8(the original position)?  :-\

Offline cooldude

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Re: Physics help!
« Reply #71 on: August 26, 2010, 02:05:15 pm »
Yup I got that. I asked for part b) The value of a is 11 :S Shouldn't it be 8(the original position)?  :-\

no, okay so first of all it is at its maximum position and it can travel a total of 22mm, that means the equilibrium position is 11mm below, now what is a, the amplitude (the maximum displacement from the mean position) so it is 11mm. and w (omega)=2*pi*f, 2*4.5*pi=9pi radians/second

nid404

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Re: Physics help!
« Reply #72 on: August 26, 2010, 02:17:24 pm »
Ahhh....ohkay that way...thanks dude..+rep  :)

Offline cooldude

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Re: Physics help!
« Reply #73 on: August 26, 2010, 02:20:13 pm »
Ahhh....ohkay that way...thanks dude..+rep  :)

oh yeah and one more thing, u can also tell its starts from the maximum position cuz its a function of cos and not sine, and Thanks for the rep ;D

nid404

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Re: Physics help!
« Reply #74 on: August 26, 2010, 02:59:13 pm »
yeah I figured that....didn't really notice what they were asking for.  :-[

Ah...one more question

June 2010 paper 4 variant 1, Q3 b) How can they say acceleration is constant ? :S Is it because a=g ? :-\