Improper integral

[@d!_†oX!©]

Probably a very easy question..but can anyone please explain what to do if the limits given to us for integration have either inifinite or -ve infinite??
Pure maths 1
Thanks in advance..i have an exam tom..please help if you can

[Alpha]

Hm, you have to analyse what happens to the value of your integrated expression when the value of x is increasing.

[Saladin]

Please give me a question as an example.

[@d!_†oX!©]

Please give me a question as an example.

here you go..

[cooldude]

here you go..

integrate the integrand first, we get (x^-1)/-1=-x^-1=-1/x
the limits are infinity and 1, when x tends to infinity y tends to 0, i.e. the integral tends to 0, therefore we get 0-(-1/1)=1

[cooldude]

oh yeah and just read it from the book, ull get it, and when the limits are infinity its an infinite integral

[Saladin]

Never tried one of these before.