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Improper integral

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@d!_†oX!©:
Probably a very easy question..but can anyone please explain what to do if the limits given to us for integration have either inifinite or -ve infinite??
Pure maths 1
Thanks in advance..i have an exam tom..please help if you can

Alpha:
Hm, you have to analyse what happens to the value of your integrated expression when the value of x is increasing.

Saladin:
Please give me a question as an example.

@d!_†oX!©:

--- Quote from: Engraved on August 12, 2010, 02:44:02 pm ---Please give me a question as an example.

--- End quote ---

here you go..

cooldude:

--- Quote from: @d!_†oX!© on August 12, 2010, 03:10:01 pm ---here you go..

--- End quote ---

integrate the integrand first, we get (x^-1)/-1=-x^-1=-1/x
the limits are infinity and 1, when x tends to infinity y tends to 0, i.e. the integral tends to 0, therefore we get 0-(-1/1)=1

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