Qualification > Math

MATH A2 P2

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Saladin:

--- Quote from: Ghost Of Highbury~ on August 09, 2010, 03:13:25 pm ---Anyone having CIE AS math P1 book.

Pg 48, Q 9e) and 9f)

Pg 50 Q 20h) and 20i)

Thank you.



--- End quote ---

Sorry, do not have the book, can you please give me a scanned copy to work with?

Ghost Of Highbury:

--- Quote from: Engraved on August 09, 2010, 04:17:28 pm ---Sorry, do not have the book, can you please give me a scanned copy to work with?

--- End quote ---

Will try..

Ghost Of Highbury:
Question : Suggest a possible equation for each of the graphs.

here

http://img707.imageshack.us/img707/103/scan0001cn.jpg

http://img197.imageshack.us/img197/4797/byhbyh.jpg

plz explain the steps to solve them too.
thanks

Saladin:

--- Quote from: Ghost Of Highbury~ on August 09, 2010, 05:09:46 pm ---Question : Suggest a possible equation for each of the graphs.

here

http://img707.imageshack.us/img707/103/scan0001cn.jpg

http://img197.imageshack.us/img197/4797/byhbyh.jpg

plz explain the steps to solve them too.
thanks



--- End quote ---

I love the names you give to your images man! Keep up the good work! :D

(e)

The line passes through two negative points and the origin.

(f)

The left side of the curve is going downward. This means that it is a negative curve. There are two interceptions where the x-axis is positive. Therefore two (x-z)s.

(g)

The left side is negative, so it the curve is negative. It has a standing point with 2 interceptions on the x-axis, so there is a somewhere. And it cuts the x-axis in the positive area. Thus, it has an (x-z).

(h)

There is a stationary point on (0,0) meaning that there is and there is an intersection on the negative part of the x-axis. So, there is a (x+z).

(i) Although this may seem intimidating, it is actually based on the simple rules as previous.

You can see that there are 6 straight line sections. So the total power of with be .

Now, there are 3 intersections in the positive and the negative, so you will have a repeated brackets of these: and

Now, determining the the slope is very important. Before you do such big ones, just plot them in your head. Now even powers e.g will always have their negative x values on the positive y-axis. So, is no exception. But the graph we see shows that the negative x values are on the negative y-axis.

So, we put in a negative sign, and problem solved! :)

Ghost Of Highbury:

--- Quote from: Engraved on August 09, 2010, 06:56:54 pm ---I love the names you give to your images man! Keep up the good work! :D

(e)

The line passes through two negative points and the origin.

(f)

The left side of the curve is going downward. This means that it is a negative curve. There are two interceptions where the x-axis is positive. Therefore two (x-z)s.

(g)

The left side is negative, so it the curve is negative. It has a standing point with 2 interceptions on the x-axis, so there is a somewhere. And it cuts the x-axis in the positive area. Thus, it has an (x-z).

(h)

There is a stationary point on (0,0) meaning that there is and there is an intersection on the negative part of the x-axis. So, there is a (x+z).

(i) Although this may seem intimidating, it is actually based on the simple rules as previous.

You can see that there are 6 straight line sections. So the total power of with be .

Now, there are 3 intersections in the positive and the negative, so you will have a repeated brackets of these: and

Now, determining the the slope is very important. Before you do such big ones, just plot them in your head. Now even powers e.g will always have their negative x values on the positive y-axis. So, is no exception. But the graph we see shows that the negative x values are on the negative y-axis.

So, we put in a negative sign, and problem solved! :)

--- End quote ---
Thanks a lot man. +rep

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