Qualification > Revison Notes

Differentiating exponentials and logarithms

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nid404:
ohkay gimme some time.

nid404:
4 D

1 f)



= 0- (-2+ ln|(-2)|
= 2-ln 2

nid404:
I'll have a nap and do the rest  ;D

nid404:

--- Quote from: mousa on July 25, 2010, 01:06:02 pm ---

Miscellaneous. 1 E., Q4,5,6,7


--- End quote ---

1) e)
   
        ln |2-x| - ln |3-x|
dy/dx= 1/2-x d(2-x)dx - 1/3-x d(3-x)/dx
       = -1/2-x + 1/3-x
       

nid404:
5)

 
 

6) y= 2x2-lnx

dy/dx= 4x- 1/x

4x-1/x= 0
4x2=1
x2=0.25
x= 0.5
       
dy/dx greater than zero...hence minimum

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