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IGCSE PHYSICS DOUBTS HERE !!!!

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The Golden Girl =D:

--- Quote from: $~SauD~$ on January 16, 2011, 04:21:36 pm ---Need Help!
Question 6, part (a)
First variant .... i would be glad if you tell me the procedure...
and if you want the formula it is ----> refractive index= sin i/ sin r :)

--- End quote ---

the refractive index is given as 1.49 in the part (b) ....and when you go back to the Image the INDEX angle is 30 degree ,and the refractive angle is UNKNOWN...use the formula as follows:

1.49 = sin 30 / sin r

sin r *1.49 = sin 30

r = sin-1 [ sin 30 / 1.49 ]

the sin-1 is done by pressing shift and then sin on the calculator ;)

and you'll get the answer =]

SauD~:
Thats easy. and i also did that way but the answer is ---> 48.2 >.<
WHY?!?!?! is that :)

SauD~:
And I would love to share, this with all...
These are notes i found on sf, but were faulty, incomplete and understandably and also added some of mines :D :D :D :D :D.....
Thanks  8)

The Golden Girl =D:

--- Quote from: $~SauD~$ on January 16, 2011, 04:32:56 pm ---Thats easy. and i also did that way but the answer is ---> 48.2 >.<
WHY?!?!?! is that :)

--- End quote ---

Maybe your calculator isn't functioning ,remember what ya told me last time ? ....ya so check it ;)

SauD~:
Answer in mark scheme is 48.2 and the answer i am getting doing that method is 19.6
>.<

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