Qualification > Sciences
IGCSE PHYSICS DOUBTS HERE !!!!
SauD~:
--- Quote from: Ari Ben Canaan on May 14, 2011, 11:30:50 am ---The link you've given isnt functioning.
--- End quote ---
oh oh, sorry
Thats not the link, this one:
http://www.xtremepapers.me/CIE/Cambridge%20IGCSE/0625%20-%20Physics/0625_w10_qp_12.pdf
elemis:
--- Quote from: $~SauD~$ on May 14, 2011, 11:58:05 am ---oh oh, sorry
Thats not the link, this one:
http://www.xtremepapers.me/CIE/Cambridge%20IGCSE/0625%20-%20Physics/0625_w10_qp_12.pdf
--- End quote ---
The reciprocal of the gradient of the graph is the spring constant since :
F=ke ; k = F/e
K in this case is equal to 2.5
If the spring length when the unknown weight is added is 16.4 :
F =ke
F = 2.5*(16.4-15)
F = 3.5 N
SauD~:
--- Quote from: Ari Ben Canaan on May 14, 2011, 12:24:11 pm ---The reciprocal of the gradient of the graph is the spring constant since :
F=ke ; k = F/e
K in this case is equal to 2.5
If the spring length when the unknown weight is added is 16.4 :
F =ke
F = 2.5*(16.4-15)
F = 3.5 N
--- End quote ---
Shukran(arabic).. Thank you... xie xie(chinese)...
NotAbod:
--- Quote from: Ari Ben Canaan on May 14, 2011, 03:53:45 am ---It is accelerating hence its velocity is increasing. Thus, its KE will increase (KE = 0.5mv2)
Since it is moving upwards it is attaining a new vertical height, hence, its GPE increases.
Answer = D
--- End quote ---
Thanks :)
rep
**RoRo**:
Can someone please explain to me how do you solve Q38 in this paper?
http://www.xtremepapers.me/CIE/Cambridge%20IGCSE/0625%20-%20Physics/0625_w10_qp_11.pdf
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