Qualification > Sciences
IGCSE PHYSICS DOUBTS HERE !!!!
The Golden Girl =D:
I'm sorry but what is it that you're waiting for ? .. Please Quote your post that hasn't been answered.
Most UniQue™:
--- Quote from: Relina on March 31, 2011, 12:25:05 am --- Thanks for the idea but i;m soorry tht i didnot mention in my previuos posts that in the question they said that the two lamps were identical so does the same idea apply
and plz do u think that when a 2A are supplied by the battery whatever lamps was there or it depends on the resistance each lamp has ??? ???
--- End quote ---
This is the question
NotAbod:
--- Quote from: Relina on March 29, 2011, 10:54:24 pm ---ammeter reads 2A
if lamp N removed the current in ammeter become less than 2A explain why???
sorry for poor drawing :(
--- End quote ---
Lamp M and N are connected in parallel.
In parallel circuits,
1-voltage is the same across each resistance, which means if the the power supply is 2v, both lamp M and N will get a 2V supply.
2-Total current supplied by the battery is equal to the sum of currents passing through each resistance or branch of the circuit.
Which means Total current = lamp M current + lamp N current
3-Total resistance of the circuit = 1/R1 + 1/R2
When lamp N is removed, we get a series circuit,
In series circuits,
1- Total volatge = V1+v2+v3
2- Total resistance = R1+R2+R3
3- Same current flows through each resistance
Lamps M and N are identical, both need same current, e.g 1A for each
when M and N are connected in PARALLEL, current= 1+1 = 2A
When only M is connected, Current= 1A
and if M and N were connected in SERIES then Current = 1A
Hope this helps ;D ;D
If ur still facing problems, then PM me
~ Miss Relina ~:
--- Quote from: AboD on April 10, 2011, 06:00:32 pm ---Lamp M and N are connected in parallel.
In parallel circuits,
1-voltage is the same across each resistance, which means if the the power supply is 2v, both lamp M and N will get a 2V supply.
2-Total current supplied by the battery is equal to the sum of currents passing through each resistance or branch of the circuit.
Which means Total current = lamp M current + lamp N current
3-Total resistance of the circuit = 1/R1 + 1/R2
When lamp N is removed, we get a series circuit,
In series circuits,
1- Total volatge = V1+v2+v3
2- Total resistance = R1+R2+R3
3- Same current flows through each resistance
Lamps M and N are identical, both need same current, e.g 1A for each
when M and N are connected in PARALLEL, current= 1+1 = 2A
When only M is connected, Current= 1A
and if M and N were connected in SERIES then Current = 1A
Hope this helps ;D ;D
If ur still facing problems, then PM me
--- End quote ---
Thanks for u Life Saver
i'll be always wait for ur convincing for ur convincing answers ;D
NotAbod:
--- Quote from: Relina on April 10, 2011, 08:09:33 pm ---Thanks for u Life Saver
i'll be always wait for ur convincing for ur convincing answers ;D
--- End quote ---
Your most welcome
2 times " for ur convincing" ? ;D
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