New servers, hooraaaay! More bandwidth, more power.
i still have a feeling i am right because, i'll show you the working:s=1.175 u=0.7 a=9.8 t=? v=?if we calculate v firstthenv^2=u^2+ 2as =0.49 + [2*9.8*1.175] = 23.52therefore v=4.849742261 ~ 4.85now using v=u+att= (v-u)/a=(4.85-0.7)/ 9.8=0.423223087 ~0.42sam i right?
and not just me, all the toppers in my class, the ones who always get full marks also got 0.42.even i was very confident, but after seeing the marking scheme, i'm kinda depressed.do you think there must be something wrong with the marking scheme?
i also got 0.42 with a similar method :S:Sand i was very confident abt it ::S:S:S
You problem is using a positive value for your initial velocity.You have to use either a negative initial velocity combined with positive acceleration and displacementORYou use positive initial velocity combined with negative acceleration and displacementI did similar workings to you... working out Final Velocity first.u=-0.7a=9.8s=1.175v=?t=?Working out VV^2=U^2 + 2asv^2=(-0.7)^2 + 2x9.8x1.175v= 4.849Then working out tv= 4.849 ( positive because its now traveling in the same direction as i choose as positive earlier)u= -0.7a=9.84.849= (-0.7)+9.8tt= 0.566sMake any sense?
how much marks will i lose for that? i mean i did everything the same way, just that i took initial vel positive and got 0.42s.
same here i too messed up tht question .. wat do u think ho many marks r we gonna lose in it