Okay, M/J 2008, question 2 part a. How do you find the gradient and y-intercept??
I almost never get them right!
rearrange the equation to give you y = mx + c
here you get ln R = ln Ro - pnx ln e
ln e = 1
so ln R = -pn x + ln Ro
-pn is the gradient and ln Ro is the y-intercept
guys it says- USE RHEOSTAT to keep current constant?
how do you do that???
yeah i don't get that either :/
Zara, i tried doing that question but i really don't get it
i know you have to plot R against 1/A though, and pl is the gradient, and that was your question right? woops my bad, that wasn't your question. well since you're varying A to get different values of R, then A is the independent variable and R is the dependent variable.
but could anyone tell me how exactly we're supposed to set this experiment up? i'm okay with the analysis and safety precautions and whatnot, just the actual experiment is like o.O