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phy p2 doubts =\

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Twinkle Charms:

--- Quote from: astarmathsandphysics on June 07, 2010, 11:15:11 pm ---3a)density=mass/volume
bi)mass=Ahp
bii)pressure=force/area=mg/A=Ahpg/A=hpg
ci)volume=mass/density so if masses are the same, colume of water vapour/volume of water=1/(1/1600)=1600
ii)cube root(1600)=11.7 remeber that volume =l^3 so l=cube root of volume
di)they have the same density
ii|)high melting point
iii)cannot deform easily, unlike liquids

--- End quote ---
Thanks astar, explain other ques also please..

Twinkle Charms:
Q2 d (ii) in O/N07,  why do we add the forces 75 and 23 and why not subtract ???

astarmathsandphysics:
jun07 di) draw a vector 18 to the right and sqrt(25^2-18^2)=17.3 down
ii)tan^(-1(17,3/18))=44 degrees

falafail:

--- Quote from: Zara on June 07, 2010, 10:57:30 pm ---aite thx vserian

so Q3 still unanswered =\

in same paper M/J07 Q4d(i) and (ii)


O/N07 Q1 b , how to calculate the uncertainty, im gettin 6.9*10^-3 whereas in ms it says 0.009 ..??

this paper is attached to the post..

--- End quote ---

i think this is how its done:

make R the subject of the formula, you get R=(V/pi X L)^1/2
to calculate the uncertainty here, you need to find the percentage uncertainty first then multiply by the value you get for R
in this case, % uncertainty in R = 1/2(% uncertainty in V + % uncertainty in L)
which is 0.019
the value you get for R is approximately 0.4886
so uncertainty = 0.4886 X 0.019 = 0.009

astarmathsandphysics:
Q2 d (ii) in O/N07,  why do we add the forces 75 and 23 and why not subtract
I dont understand your question
use P=Fv=23*4.5=103.5W

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