Author Topic: CIE AS Chemistry P1 Doubt  (Read 914 times)

Offline Chingoo

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CIE AS Chemistry P1 Doubt
« on: June 07, 2010, 01:26:41 pm »
Hi!
I am unable to solve Question 28 in Chemistry Paper 11 October November 2009 (CIE). Please explain!
All that is on earth will perish:
But will abide (forever) the Face of thy Lord--full of Majesty, Bounty & Honor.
Then which of the favors of your Lord will ye deny?


Qura'n, Chapter 55: The Beneficent, Verses 26-28

Offline Chingoo

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Re: CIE AS Chemistry P1 Doubt
« Reply #1 on: June 07, 2010, 10:11:55 pm »
Is just one question, pretty please.  ;D
All that is on earth will perish:
But will abide (forever) the Face of thy Lord--full of Majesty, Bounty & Honor.
Then which of the favors of your Lord will ye deny?


Qura'n, Chapter 55: The Beneficent, Verses 26-28

Offline sabrina

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Re: CIE AS Chemistry P1 Doubt
« Reply #2 on: June 08, 2010, 01:33:28 pm »
same doubt. someone plz xplain

Offline CHEMMASTER6000

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Re: CIE AS Chemistry P1 Doubt
« Reply #3 on: June 08, 2010, 02:48:25 pm »
cant down load mind posting the question

Offline sabrina

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Re: CIE AS Chemistry P1 Doubt
« Reply #4 on: June 08, 2010, 02:53:58 pm »
cant down load mind posting the question
here it is :)

Offline Chingoo

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Re: CIE AS Chemistry P1 Doubt
« Reply #5 on: June 09, 2010, 08:23:00 am »
Sad to see no answers, but I thought over it again and I think this is the concept.

Basically, we have to keep the mechanism of nucleophilic addition in our mind. A nucleophile (with a lone pair and sometimes a negative charge) attacks the <C=O> as C is slight +ive due to a polar bond between C and O. Carbon 'throws' the electrons of the pi-bond to oxygen as it has a slight negative charge--think of it as a haughty husband divorcing his wife and giving her the kids. It is then marries--rather bonds with the nucleophile. This forms a carboanion (I think the spellings are wrong). Then, the latter part of the nucleophile (which is basically an electrophile) attacks the oxygen. CN- is a nucleophile too and hence follows this mechanism, along with H+ which attacks the O- (basically having an additive electron from the pi-bond).

Now replace CN- with -CH2CH2CO2 (basically, the negative charge is on the CH2 NOT bonded to CO2). It plays the same role as CN-, and we get C as the answer. I think the usage of weak and strong base is not really related to this solution, and even if it is it is not necessary to solve this.
All that is on earth will perish:
But will abide (forever) the Face of thy Lord--full of Majesty, Bounty & Honor.
Then which of the favors of your Lord will ye deny?


Qura'n, Chapter 55: The Beneficent, Verses 26-28