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Chemistry Paper 1 problems...

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CHEMMASTER6000:
26. ok so if you put the Oh on the 2nd or 3rd carbon after oxidation you will not get 4 oxygen . either a 3 02 OR 2 O2 SINCE YOU ONLY FORM KETONE. itbasically to math the C4H6o4 given

27. dehydration is the same as elimination and thus an alchahol forms and alkene. so you must try to deduce which one could have a tertairy alchahol . in this case D would have form the tertiary alchahol

28. i think for this case you might have put B but hte answe is C those sneaky cie peple . the H- indicates the CN and in the machanism its the Cn which attacks first.

32. its D because catalysts dont eveft KP or KC cause they worl both ways in the reaction . 3 indicates increasing activation enerygy which is wrong cause strictly speaking, catalst lowers activatoin energy.

40. 1 is a base so reacts with the acid. the rest reacts with alkene

CHEMMASTER6000:
 ;D hope that clears things up

CHEMMASTER6000:
by the way R is fixxed at 8.31. thing abotu this questoin is that even by using Pv=nrt the answer cant be produce

nox_fjmoony:
@:CHEMMASTER6000: Thanks a lot for all your help man, really appreciate it. And if you're giving any exams or whatever, best of luck to you:D Thanks again...and indeed those sneaky CIE folks XD

Yeah, thats what I was wondering, since R is a constant, and yeah using pv=nRT you can't get that answer, though you do get it with the method outlined by tmisterr, though I still don't understand why we have to find a separate value of R for that :\
Oh well.

Thanks all.
Good night.
And Good luck ^ ^

ruby92:
can someone explain o/n 2006 q 9 and 21
o/n 2008
22 and how is 3 posibble for 32?

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