Qualification > Sciences
P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
Meticulous:
--- Quote from: halosh92 on June 08, 2010, 01:15:13 pm ---shouldnt we mention something about coherence??
and r u sure about the formulas isnt it for constructive:
path difference: n lamda
and destructive:
path difference= (n + 1/2) lambda and phase differnce = pie
--- End quote ---
coherent means same frequency
poisonedrose:
--- Quote from: sabrina on June 08, 2010, 01:10:17 pm ---guys how to do o/n2008 q7bii
--- End quote ---
We know that the 2000 resistor has 3.6volts, so we subtract 6 from 3.6V giving us 2.4V
As the thermistor and 5000R are in parallel, they have the same voltage of 2.4V
Using the ratio method, we can do
3.6 : 2000
2.4 : x
Finding x- which is 1,333 (the resistance of both of the devices)
From that, we use the combination resistance formula
5000*R2/5000+R2=13333
And with that, we can simply and find out R2- which is the resistance of the thermistor.
sabrina:
--- Quote from: halosh92 on June 08, 2010, 01:15:13 pm ---shouldnt we mention something about coherence??
and r u sure about the formulas isnt it for constructive:
path difference: n lamda
and destructive:
path difference= (n + 1/2) lambda and phase differnce = pie
--- End quote ---
i m sorry abt the constructive interference.forgot to put "n".
abt destructive the formula of my best of knowledge is correct
abt coherent sources = the interference should have constant phase difference to have observable interference. i think that's it.
sabrina:
--- Quote from: poisonedrose on June 08, 2010, 01:19:54 pm ---We know that the 2000 resistor has 3.6volts, so we subtract 6 from 3.6V giving us 2.4V
As the thermistor and 5000R are in parallel, they have the same voltage of 2.4V
Using the ratio method, we can do
3.6 : 2000
2.4 : x
Finding x- which is 1,333 (the resistance of both of the devices)
From that, we use the combination resistance formula
5000*R2/5000+R2=13333
And with that, we can simply and find out R2- which is the resistance of the thermistor.
--- End quote ---
thanks alot :)
halosh92:
--- Quote from: sabrina on June 08, 2010, 01:24:41 pm ---i m sorry abt the constructive interference.forgot to put "n".
abt destructive the formula of my best of knowledge is correct
abt coherent sources = the interference should have constant phase difference to have observable interference. i think that's it.
--- End quote ---
alright thx :)
Navigation
[0] Message Index
[#] Next page
[*] Previous page
Go to full version