Qualification > Sciences

P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE

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sizbeauty:
@ sabrina,
nopz u did it wrong way,
it shuld b lik if for 6*10^23 atoms,u hav 10.7cm^3 vol
so for 1 atom,it shuld b x cm^3 vol..i.e
6*10^23=10.7
1=x
and thn u can get ur ans by cross multipling n for separation,whnver v r givn the vol,v take the cube root of it so it would b (1.78 x 10^-23)1/3 =2.61 x10^-8
hope it helped :)

cn u plz luk at ma ques???

ruby92:
m/j 2007
2 d

The SMA:
m/j 2006 p2 Q6b), why do we need to times 2 the wavelength, using v=f x lambda
and for part a) how to draw the waves?

sabrina:

--- Quote from: sizbeauty on June 08, 2010, 10:50:44 am ---@ sabrina,
nopz u did it wrong way,
it shuld b lik if for 6*10^23 atoms,u hav 10.7cm^3 vol
so for 1 atom,it shuld b x cm^3 vol..i.e
6*10^23=10.7
1=x
and thn u can get ur ans by cross multipling n for separation,whnver v r givn the vol,v take the cube root of it so it would b (1.78 x 10^-23)1/3 =2.61 x10^-8
hope it helped :)

cn u plz luk at ma ques???

--- End quote ---
thanks a lot now i got it

halosh92:

--- Quote from: ruby92 on June 08, 2010, 11:17:33 am ---m/j 2007
2 d

--- End quote ---

this is sort of like the projectile
now the electron is exactly in the middle of the plates initally , vertical distance= 1.5cm
so if it has to travel upwards it will travel 1.5/2
right?
which is 0.75 cm basically so....
horizontal velocity is given in the question BUT vertical velocity in projectile cases ( why projectile? because its travelling in a curved path towards the upper plate) the vertical velocity is = 0
so s=ut + 1/2at^2
u=0 as i mentioned
s= 1/2 * (ure "a" value) *( ure "t" value) ^2
u will get an answer which is less than 0.75cm so obviouslly it will hit the plate
got it?
remember to change cms to ms

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