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P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE

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astarmathsandphysics:
nov 09
7ai)R
ii)R/2 since BY is in paralell with CX
iii)R+R/2+R since AB is in series with YZ and the paralell circuit between Band Y
bi)I_1+I_2=I_3
ii)E_=I_1 R+I_2 R by applying V=IR to the two resistances
iii)E_1-E_2 =I_1 R -I_2 R +I_1 R
net voltage is E_1 -E_2 and apply V=IR to each (remeber I_2 is in opposite direction so negative)

Chingoo:
Thanks a lot!

hesho21:
Guys plz Nov 07 , 4c , I dont get the bubble thing at all !

astarmathsandphysics:
breaking stress=9.5*10^7=F/A=1900/A so A=1900/9.5*10^9=2*10^-6 =actuall cross section of metal
3.2*10^-6-2*10^-6=1.2*10^-6=cross section of bubble

hesho21:

--- Quote from: astarmathsandphysics on June 07, 2010, 11:59:32 pm ---breaking stress=9.5*10^7=F/A=1900/A so A=1900/9.5*10^9=2*10^-6 =actuall cross section of metal
3.2*10^-6-2*10^-6=1.2*10^-6=cross section of bubble


--- End quote ---

can i ask why did u subtract at the end the areas?

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