Qualification > Sciences
P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
halosh92:
--- Quote from: zxcvbnm on June 07, 2010, 07:36:46 pm ---here...i did figure it out but not sure if i'm right
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Q1 ??? there is no such similar question
do u mean Q8?
zxcvbnm:
oh sorry! i meant 7...the one where we have to use kirchoff's second law....i figured it out....current entering=current leaving...but if you could still have a look
halosh92:
--- Quote from: zxcvbnm on June 07, 2010, 07:54:54 pm ---oh sorry! i meant 7...the one where we have to use kirchoff's second law....i figured it out....current entering=current leaving...but if you could still have a look
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yep its correct see if we take anticlockwise direction starting from E1
current is in the same direction so it will be
-I1R and then it faces the (+) terminal of E2 so we take it as negative so next is -E2
then we face the next resistor but here the current is moving in the opposite direction to our clockwise direction so it will be + I2R
then we face the next resistor, so the the current is the same direction to our chosen direction so it will be -I1R
and we then face the negative terminal of E1 so we take it as +E1
so we group them together
-I1R-E2+I2R-I1R+E1=0
got it?
zxcvbnm:
yup, thanx~!
halosh92:
--- Quote from: halosh92 on June 07, 2010, 02:02:07 pm ---could anyone solve this??? ??? ??? ??? ??? ???
[/quote/]
someone PLZ PLZ DO THIS :(
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