Qualification > Sciences

P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE

<< < (21/39) > >>

sizbeauty:
can sm1 plz help me out wid june08:
Q4(part c)
Q6(part b)don't we just add up the powers???

zxcvbnm:
june 09, variant 1, question 5,b

sweetie:

--- Quote from: zxcvbnm on June 07, 2010, 06:36:51 pm ---june 09, variant 1, question 5,b

--- End quote ---

https://studentforums.biz/index.php/topic,8636.60.html

zxcvbnm:

--- Quote from: nid404 on June 06, 2010, 05:14:45 pm ---
phase difference=( 2pi/ lamda)  X path difference

phase difference = pi [ for destructive interference]
lambda(wavelength) = 2pi/ pi  X path difference.
path difference is S2M - S1M 
find S2M using Pythagoras = root of 802 + 1002
                                                   =128
path difference= 128-100=28
wavelength= 2pi/pi X 28
               =56cm                 
At f= 1KHz wavelength= 0.33m/ 33cm
At f=4kHz   wavelength= 0..0825/8.25cm
wavelength changes from 33cm to 8.25cm
for minima...phase difference should be either one of them pi, 3pi,5pi,7pi [sub them in the eqn]
minima is observed when lambda= 56cm, 18.7cm, 11.2cm, 8cm
which are the 2 values between 33 and 8.25?? 18.7 and 11.2...so only 2 minimas


--- End quote ---

thankyou sweetie and nid!
but where did you get the formula from? for phase difference?

zxcvbnm:
oh i realised that we can also use (2n+1)(lambda)/2...but i've forgotten what the n stands for...please clarify this asap!

Navigation

[0] Message Index

[#] Next page

[*] Previous page