Qualification > Sciences
IGCSE CHEMISTRY DOUBTS
Ivo:
Please can somone answer my doubtful doubt! :P
For varying concentrations of acid in reactions and looking at rates, why sometimes when they sketch a graph, increasing the concentration of acid still has same amount of product (gas) produced, but other times, when double concentration, the gas volume doubles?
Majorly confused. How about with surface area and temperature, do they have an effect on the final amount of gas produced?
Vin:
--- Quote from: Nidzzz on June 06, 2010, 10:49:02 pm ---http://www.xtremepapers.net/CIE/Cambridge%20IGCSE/0620%20-%20Chemistry/0620_w09_qp_31.pdf
5c(ii) can ny 1 help wid de equation
--- End quote ---
4
OK, Ge4H10 is like any other Alkane which forms CO2 and water.. but it this case its GeO2
Complete combustion
C4H10 + 13 O2 --> 4CO2 + 5H2O
Ge4H10 + 13 O2----> 4 GeO2+ 5H2O
Vin:
--- Quote from: Ivo on June 06, 2010, 11:18:26 pm ---Please can somone answer my doubtful doubt! :P
For varying concentrations of acid in reactions and looking at rates, why sometimes when they sketch a graph, increasing the concentration of acid still has same amount of product (gas) produced, but other times, when double concentration, the gas volume doubles?
Majorly confused. How about with surface area and temperature, do they have an effect on the final amount of gas produced?
--- End quote ---
OK, I get a part of your ques. Is this what you are looking for?..
Zn + 2HCl ---> ZnCl2 + H2
Conc. for acid doubled, but same amount of Zn used reaction faster but results in same volume of H2 gas.
Doubling the amount of both reactants results in doubling of product (gas).
Surface area and Temperature doesn't have anything to do with the yield, they only influenced the rate of reaction. Posting a q. as an example would do good as I still cannot properly get your question. Usually in the ques it is mentioned right, when the conc of reactants in increased/decreased.
Ivo:
--- Quote from: ~VIN1094~ on June 06, 2010, 11:28:55 pm ---OK, I get a part of your ques. Is this what you are looking for?..
Zn + 2HCl ---> ZnCl2 + H2
Conc. for acid doubled, but same amount of Zn used reaction faster but results in same volume of H2 gas.
Doubling the amount of both reactants results in doubling of product (gas).
Surface area and Temperature doesn't have anything to do with the yield, they only influenced the rate of reaction. Posting a q. as an example would do good as I still cannot properly get your question. Usually in the ques it is mentioned right, when the conc of reactants in increased/decreased.
--- End quote ---
Hmm, I'm still a bit confused. Maybe a question example might help. w02, Q2) c) ii) and iii)
Vin:
--- Quote from: Ivo on June 06, 2010, 11:31:02 pm ---Hmm, I'm still a bit confused. Maybe a question example might help. w02, Q2) c) ii) and iii)
--- End quote ---
OK here, look at the reaction. Its the decomp. of H2O2. Doubling the conc. of H2O2 increases the amount of oxygen in H2O2 by twice. Hence when
it reacts with H2O2 decomposes there is now twice the number of O2 produced.. got it?
Also when amount of catalyst is halved the reaction is slower. As you know a catalyst never takes part in a reaction so it really doesn't affect the amount of O2 produced.
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