Qualification > Reference Material
Add Maths June 8, 10 2010
holtadit:
What year is this from A@di
Ghost Of Highbury:
--- Quote from: J.Darren on May 30, 2010, 01:10:06 pm ---Right that means I have made a mistake somewhere, mind pointing it out for me? :)
--- End quote ---
lemme check...from what i saw, ur diagram is incorrect..considering 315 as the bearing the angle b/w the liner and lifeboat path shud be 135 degree which is obtuse, its acute in ur diagram...gotta extend the 90km line till the angle made by the third line is obtuse to the 54 km line
Ghost Of Highbury:
and how did u get 45 degree in ur diagram?? it shud be 19.9 , check mine ..
holtadit:
My exact answer is 28 13/15 km/h
Is that right ?
J.Darren:
--- Quote from: A@di on May 30, 2010, 01:23:37 pm ---and how did u get 45 degree in ur diagram?? it shud be 19.9 , check mine ..
--- End quote ---
The ship is travelling at a bearing of 090, and it is 90km away from the lifeboat at the time of the call of distress. The liner is also on a bearing of 315 from the ship. When you draw the diagram, you can mark down 45 degrees twice - one is between the 54 km and the 90 km, and one is between the 90km and the normal at that point. I am guessing that you have made an assumption that the ship is at a bearing of 315 from the lifeboat AFTER it has moved 54 km ...
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