Chemistry question

[yasser37]

Hi guys


Nov. 02

Q. 4

Part e

[yasser37]

also Q.6 Part b ii

[nid404]

4)e) H2O(l) + CO(NH2)2(aq) ? CO2(aq) + 2NH3(aq)
       –287.0 + –320.5              –414.5        –81.0 X 2

Enthalpy of products= -414.5-(81X2)=-576.5kJ
Enthalpy of reactants= -287-320.5=-607.5 kJ

     
= -576.5kJ- (-607.5)=+31 kJ/mol

[nid404]

6)b) ii)

C₅H₁₁OH + NaBr------> C₅H₁₁Br+ NaOH

Molar Ratio of C₅H₁₁OH : C₅H₁₁Br  is 1:1

Yield is 60%

15g of C₅H₁₁Br = 15/Mr  moles Mr of bromopentane=151g
no of moles= 15/151 = 0.1 approx

since yield is 60%

60/100 X no of moles of C₅H₁₁OH = 0.1 moles of  C₅H₁₁Br

no of moles of C₅H₁₁OH= 0.166 moles
Mr of C₅H₁₁OH= 88g
Mass of C₅H₁₁OH required= 0.166X 88=14.7 g

[unknown 101]

i wouldve helped you, but she answered faster!!   

[moon]

can somebody help me to solve question no. 3 and Q1(c), (d), (e), (f) in ppr 52 Nov. 09.
thanx in advance.

[nid404]

I'm doin AS...so p5 is greek to me

[moon]

ok thanx a lot..