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Hasnainali:
http://www.freeexampapers.com/FreeExamPapers.com_.php?__lo=TyBMZXZlbC9QaHlzaWNzL0NJRS8yMDA4IEp1bi81MDU0X3MwOF9xcF8xLnBkZg==

plz explain so8 q8

nid404:
Moment= Force X perpendicular distance from the pivot.

F=2N

perpendicular distance=QC=0.3m

So moment=2X0.3=0.6Nm  A

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