Author Topic: MATHS P 3 HELP MJ 08  (Read 741 times)

Offline AndrewCedric

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MATHS P 3 HELP MJ 08
« on: May 21, 2010, 12:38:45 pm »

Offline Twinkle Charms

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Re: MATHS P 3 HELP MJ 08
« Reply #1 on: May 21, 2010, 07:05:08 pm »
1/z=1/(2costheta+i(1-2sintheta))
1/(z+2-i)=1/[2costheta+i(1-2sintheta)+2-i]
            =1/[(2costheta+2)+i(1-2sintheta-1)]
            =1/[2(1+costheta)+i(-2sintheta)]
            =1/[2(1+costheta-isintheta) * conjugate of the denominator/conjugate of the denominator


solve this ull reach to
1+costheta/[4(1+costheta) + isintheta/4(1+costheta) = 1/4 + i sintheta/4(1+costheta)


therfore real part is 1/4 which is a constant...

get it? if u have problem with the conjugation do tell...           
You See - You like - You try - You fail meanwhile I see - I like - I want - I get!

La Fata Illa Ali, La Saif Illa Zulfikar . (:

Offline AndrewCedric

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Re: MATHS P 3 HELP MJ 08
« Reply #2 on: May 22, 2010, 03:10:20 am »
THANKS A LOT !!!!!!!!!!

Yea no more problems.
At first, I omitted the i in the denominator cause i think it wont be needed for the answer.
So i guess, you have to just plug all of them in and
finally simplify the Real part at the end only..

THANKS AGAIN !!!!!
Good Luck for Stats and Maths P3 if you're taking those !! :D :D :D :D :D

Offline Twinkle Charms

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Re: MATHS P 3 HELP MJ 08
« Reply #3 on: May 22, 2010, 08:38:46 am »
yea im taking those as well Thank You =)
You See - You like - You try - You fail meanwhile I see - I like - I want - I get!

La Fata Illa Ali, La Saif Illa Zulfikar . (: