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Math Paper 4

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ismailb_1993:

--- Quote from: pap19 on May 18, 2010, 02:25:06 pm ---pls tell me fast hot to do entire question no3 of maths paper 4 oct/nov 2000

--- End quote ---

you can use the cos rule for the first question...you know three of the lengths of the triangle that is 4,5,6. calc as follows:

to find abc
(4^2+5^2-6^2) / (2x4x5)

when you get the answer of that you use cos^-1 and you get the angle ABC

for B.) and C.) ill have to draw it which i obviously cant do here.

Saavya:
'Common Difference' Sequences

The general term for term number 'n' , common diff. 'd' and first term 'a'is:

dn + (a-d)

Find the nth term in this sequence : 13, 20, 27, 34, 41, 48 ...

a=13, d= 7

nth term = dn + (a-d) = 7n + (13-7) = 7n +6

this is one way of finding the nth term but its long i knoww

i get confused with the other ones though

Aayesha:
yeah ..but how to find it when there is no common difference between the terms ???? ???

ismailb_1993:

--- Quote from: Aayesha on May 18, 2010, 03:02:10 pm ---yeah ..but how to find it when there is no common difference between the terms ???? ???

--- End quote ---

those are the other ones she's talking about :(

ismailb_1993:

--- Quote from: Saavya on May 18, 2010, 02:44:14 pm ---'Common Difference' Sequences

The general term for term number 'n' , common diff. 'd' and first term 'a'is:

dn + (a-d)

Find the nth term in this sequence : 13, 20, 27, 34, 41, 48 ...

a=13, d= 7

nth term = dn + (a-d) = 7n + (13-7) = 7n +6


this is one way of finding the nth term but its long i knoww

i get confused with the other ones though


--- End quote ---

thanks alot!!! thats really helpful!!

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