Qualification > Math

help! mechanics 2morrow.

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anne:
a straight footpath makes an angle alpha with the horizontal. An object P of weight 1250N rests on the footpath.The coefficient of friction between the object and the footpath is 0.1 The least magnitude of a force acting up the footpath, which will hold the object at rest on the footpath is 50N. By treating the object as a particle, show that the value of alpha satisfies:
10sinaplha - 10cosalpha =0.4
can somebody do this question!!?..i tried doin this..but got sinalpha - cosalpha =0.4
the 10 was missing :P

anne:
^^^^ 10sinalpha - cosalpha =0.4

anne:
anybody home????? OMG  ???

cooldude:

--- Quote from: anne on May 18, 2010, 03:31:32 pm ---a straight footpath makes an angle alpha with the horizontal. An object P of weight 1250N rests on the footpath.The coefficient of friction between the object and the footpath is 0.1 The least magnitude of a force acting up the footpath, which will hold the object at rest on the footpath is 50N. By treating the object as a particle, show that the value of alpha satisfies:
10sinaplha - 10cosalpha =0.4
can somebody do this question!!?..i tried doin this..but got sinalpha - cosalpha =0.4
the 10 was missing :P

--- End quote ---

let coefficient of friction=c, and alpha=x
therefore R=1250cosx, F=cR
therefore 1250sinx-F-50=0
1250sinx-125cosx=50
now divide both sides by 125-.
ull get 10sinx-cosx=0.4

anne:
thanx alot!! :D

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