Qualification > Math

M.e.c.h.a.n.i.c.s

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Ghost Of Highbury:
Thanks a lot.

DaYmN:

--- Quote ---let the resistance to the cart=R
therefore X-R=0, X=R
3X-R=ma, 3X-R=800*0.8
2R=640
R=X=320
2X-R=800a
320=800a
a=0.4
v=u+at
5=2+0.4t
t=7.5 sec
--- End quote ---

That's genius! thank yu very much!  ;)

preity:
i need help for Q6 O/N 03 paper?plssss

cooldude:

--- Quote from: preity on May 16, 2010, 09:18:15 am ---i need help for Q6 O/N 03 paper?plssss

--- End quote ---

a) resolve horizontally and vertically about M-->
horizontally - let tension in BM=T
                  AM=K
Ksin30+Tsin30=10
K+T=10
vertically - Tsin30-Ksin30=0
T=K=5

b) let coefficient of friction=c
resolving vertically about B
Tcos30-F=0.2*10
F=cR
R=T*sin30=2.5
F=2.5c
5cos30-2.5c=2
therefore c=0.932
 
c) T=5
F+5cos30=2+10m
F=Tsin30=2.5
5cos30+(2.5*0.932)=2+10m
m=0.466 kg

chocolatesss:

--- Quote from: A@di on May 15, 2010, 03:19:22 pm ---One horse pulls with a force of X N, a cart of mass 800 kg along a horizontal road at constant speed. Three horses, each pulling with a force of X N, give the cart an acceleration of 0.8m/s^2. Find the time it wd take for 2 horses to increase the speed of the cart from 2m/s to 5m/s, given that each horse pulls with a force of X N and that the resistance to motion has the same constant values.

--- End quote ---
did u make up this question or is it a prediction.???

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