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P1 pure math CIE Help June 09 question 4

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doubtigetastar:
I don't know how to find a,b,c any help is appreciated :D

nid404:
ohkay

c is the y-intercept. So, you get this first as +3

The equation of the given graph reduces to y=a sinbx +3


Functions of the form f(x) = a sin x are dilation of the curve sin x parallel to the y axis.
Now the normal graph of sin(x) lies between – 1 and + 1.
In the graph we have been given that the graph lies between + 9 and -3
So the graph has been dilated 6 times. Thus a = 6.

The equation of the given graph reduces to y = 6 sin(bx) + 3

Functions of the form f(x) = sin(bx) are dilation of the curve sinx parallel to the x – axis.
This means that the period of the graph is altered.
The graph of f(x) = sin(bx) will show b cycles in 2 radians meaning that its ...
period will be given by T= /  
T of the graph is  
b=2


The equation of the given graph reduces to y = 6 sin(2x) + 3
Comparing with the graph of y = a sin(bx) + c  we get a = 6, b = 2 and c = 3.

doubtigetastar:
Thank you:)

nid404:
Not a problem  ;)

highly_ambitious:
nid404 thanks yar..for solving this question...this questions disturbed me alot....Thanks u!!!!!!!!!!

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