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CIE AS LEVEL Math..

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Stay10:
Thanks.. :)

Stay10:
came across another question from the same paper..question 9..dont get the markin scheme..ll be w8in..

immortal:
9>Area of region
    Area of square-area under graph
     (2*1)-(Integration of (3x+1)1/2 by 0,1)
     2-[2/9*(3X+1)3/2],0,1
     =4/9
ii> Volume of region
     volume of cylinder-volume under graph
     Pi*2*2-Pi integration of [(3x+1)1/2]2 to 0,1
     4Pi-Pi[1/6*(3x+1)2] to 0,1
     4Pi-Pi[8/3-1/6]
     4Pi-2.5Pi   
     1.5Pi

iii> Differentiate da eqn & substitute point of x to find da gradient
     for x=1  m=3/4                                        for x=0   m=3/2
tanQ=3/4                                              tanQ=3/2
Q=36.87                                                           56.31
Thare4 Acute angel =56.31-36.87
                           =19.4
[tanQ because gradient is also =y/x]
                         

Stay10:
Thank You ! :)

Meticulous:
That's considered as SPAM I guess. Posting with smileys only. Check with a moderator/ an administrator.

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