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thecandydoll:
Can anyone help me with the vectors questions IN CIE MATH
QP NOV 2008

Meticulous:
Which question?

astarmathsandphysics:
And paper

nid404:

--- Quote from: thecandydoll on May 09, 2010, 03:34:32 am ---Can anyone help me with the vectors questions IN CIE MATH
QP NOV 2008

--- End quote ---

check all the attachments...

PA=PE+EO+OA
   =-8j-6k-6i

PA= -6i-8j-6k

------------------------

PN=PE+EO+OD+DN

PN=-8j-6k+6i+10j
PN=6i+2j-6k

-------------------------

Calculating the angle

The dot product of the vector is given by
a.b=|a|.|b| cos

PA.PN=|PA|.|PN| cos

= PA.PN/ |PA|.|PN|

PA= -6i-8j-6k

PN=6i+2j-6k

|PA|=
      =

|PN|=
|PN|=
= [(-6i-8j-6k) X (6i+2j-6k)] / 

= (-36)+(-16)+(36)/
                            =-16/
  =  -0.157377895
      = 99.05473251°             

Hope this helps :)   

                   
                             

thecandydoll:
I really dont know to how to get the values?!!?!
i understand solving 2d vectors
But when the image is given i just cant.
how should i proceed!

cie as p1,nov 2007 :)
please,explain
Thank you.

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