It's not 36531 ... it's actually 3400 (according to my teacher that is
) which is the peak for the OH in an Alcohol
Since it can be Oxidized then it's either
primary or
secondary Alcohol ,tertiary can NOT be oxidized remember
Draw butanol ,the primary , the secondary versions of it [if you are having trouble doing that let me know I'll draw it bas mikasila for now
..u r right I'm lazy
)
if you look at the spectrum for X in part (b) of the Question. Counting them from the left to right ,they are five splittings.
Splitting one => the one with 6 lines lined up closely to each other
splitting two => the Single long line
splitting THREE => the ones with 5 lines lined up closely to each other
Splitting FOUR => those TWO parallel LONG lines
Splitting FIVE => the three lines , having the middle one the LONGEST among them
CH3CH2CH(OH)CH3starting from the LHS :
The first CH
3 => is a triplet which is the (one with three lines and the middle one the LONGEST among them
)
the CH
2 => is a Pentate [search for the ones with FIVE lines closely lined up together) ...that's the one for it
the CH => is a Sixtet [search for the ones with SIX lines closely lined up together ]
the OH => the single line ...cuz OH is ALWAYS a single line since it's a
singlet By the way
the LAST Ch
3=> is a Doublet [ search for the one with ONLY TWO lines ]
I hope I helped (: [jawabt su2aleek ana willa kunt bas 2atfalsaf o.O ]
(gtg go my own way
..cya good luck with tomorrow
)
Don't forget to include me in your prayers sis