Ohhh
....I feel so embarrassed now
It didn't strike me
This is a little difficult to explain so I got this from the net...hope you get it
It is a type of electron delocalization. Since electrons repel, if the electrons spread out, it can lead to greater stability.
In order for resonance to occur, you need to have a double bond (mobile high electron density) and a nearby orbital where the double bond can spread out to.
For example, in the following ion
H3C-CH=CH-CH2+
the double bond will be attracted to the positive charge and ends up spread out across two adjacent bonds.
H3C-CH=CH-CH2+ <---> H3C-CH-CH=CH2 (+ charge on carbon2)
Since the electrons are spreading out between the two states ("resonance structures") above, neither of those structures are really a good way to represent the molecule. The closest model of the molecule is a hybrid of the two, with the electrons smeared out over both spots where the double bond can exist. So, they are really each like a bond-and-a-half.
I got this from yahoo answers. I hope you understood.
If you don't understand, I can use benzene as an example which will be more convenient for me to explain.