Edexcel PHYSICS Doubts

[The Golden Girl =D]

The Teacher said its Something Completely New but we need to know it -.-

I hope the Pictures are Not Blurry =]

Attached .

I've got FOUR forces ,that I want to reduce to THREE to be able to draw a vector diagram *in my words - triangle showing the forces*

Since the  Lift's Arrow is LONGER than the Weight it means it's GREATER in terms of Value.

LIFT : Hence we can reduce it into ONE force which is the Lift, which is UPWARDS


the Drag to the RIGHT

the tension slightly to the LEFT

third Question : is another example so never mind.

[Vampire-Love4ever]

the Question is Wrong , I know it sounds Weird but it's supposed to be at Point B instead of C.

Explanation ;

For a Circular Path :

You Have to move AWAY from the center . You will be Pushed to the left side (direction of motion)

Let me know if you don't get it ?

Answer is A.

[The Golden Girl =D]

Answer is A.

Yes 

[Vampire-Love4ever]

I think the Question is Incomplete , but I'll answer from my copy
 
Weight is 750 N -> value from the Graph in the Question

Attached to show you how I calculated it.

Here's the Drawing:

An Arrow going UPWARDS showing R -> 250    how => 750 N - 300 N = 250 N

An Arrow DOWNWARDS which is LONGER *because she is crouching- i.e exerting MORE force # -> 750 N

# => Weight does NOT change unless he's in another planet.

700-300= 450N


Plus, I get R at 1.2s as 340N!

[Vampire-Love4ever]

I've got FOUR forces ,that I want to reduce to THREE to be able to draw a vector diagram *in my words - triangle showing the forces*

Since the  Lift's Arrow is LONGER than the Weight it means it's GREATER in terms of Value.

LIFT : Hence we can reduce it into ONE force which is the Lift, which is UPWARDS


the Drag to the RIGHT

the tension slightly to the LEFT

third Question : is another example so never mind.

Thanks! Got it now!

[Vampire-Love4ever]

Graph : the Lines are STRAIGHT , but I couldn't manage to do that ,Sorry about that.


distance = about 100  -> based on my calculations , so I assume it's 150 ,i'll make it easier for us to draw.


Attached .

Why is the speed maximum at 1.5s? :S

[The Golden Girl =D]

Why is the speed maximum at 1.5s? :S

Where in the Graph is the Gradient STEEPEST , at about 1.5 , that's why.


when you solved a]i) I did it as follows ;

V_max= delta distance/ elta time
                      = (80 - 20) / (1.6 -1.0)
                      = 100

l.6 -1.0 => 1.5 cm/s

[The Golden Girl =D]

700-300= 450N

Plus, I get R at 1.2s as 340N!

me too  

I'll let Someone look into this.

[Vampire-Love4ever]

Where in the Graph is the Gradient STEEPEST , at about 1.5 , that's why.


when you solved a]i) I did it as follows ;

V_max= delta distance/ elta time
                      = (80 - 20) / (1.6 -1.0)
                      = 100

l.6 -1.0 => 1.5 cm/s

I did: 120/(1.9-0.9)= 120cms^-1

So for ii part I use the maximum speed of120 at 1s. Will it be right?

[Vampire-Love4ever]

me too  

I'll let Someone look into this.

I'll be waiting

[Vampire-Love4ever]

can you get me the range Please from the MS .

usually if they said Estimate , the Question will have a WIDE range of answers and hence it'll be fine I guess. =]

Did you get how to do this? =s

[The Golden Girl =D]

Did you get how to do this? =s

Attached .

This is weird 0.o -> well let someone look into it.

[The Golden Girl =D]

I did: 120/(1.9-0.9)= 120cms^-1

So for ii part I use the maximum speed of120 at 1s. Will it be right?

MS says :

Sketch graph
Shows:
Speed increasing from 0 and then decreases
Max speed at correct time (accept between 1.0 and 1.5 s) OR
correct magnitude (must be indicated)
Speed decreasing to 0 at between 3.4 and 4.0 s


so I guess it's right then

[The Golden Girl =D]

It might take time ,it seems they're Not Online at the moment.

[Vampire-Love4ever]

It might take time ,it seems they're Not Online at the moment.

It's ok. I'll be waiting.
Thanks alot for your time and help. I'll pray for your exams