Qualification > Sciences
Edexcel PHYSICS Doubts
The Golden Girl =D:
Thanks =]
Will be waiting iA =D
Malak:
11 c - From the question we know what happens in the decay
We know that a lambda particle and anti-proton in produced
so the equation will be:
(any letter, I used B) = (the symbol for lambda) + (the symbol for anti-proton)
We can use any letter 'cause meson is a group and therefore it doesnt have a specific symbol.
If you check the markscheme, the 2 marks are only for the RHS.
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13 a - I was never good with these motor questions so I hope someone else will explain better :-[
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14 e - (unit 2)
Emission spectra are porduced when electrons are exicted - jump to higher energy levels and then de-excited, reutring to their orignal state, releasing energy in the process.
Why is it X-ray ---> Not reallu sure about this part
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15 - ii (attached) discharging curve of capacitor for current (you should learn these) :D
how to find the values:
Max current = V/R
10/5000 = 0.002 = 2 mA
then, Q says that typical values so we can find the the time constant
To find 37% of the original current, simply multiply by 0.37 and you will get 0.74
to find the time i takes to fall to this current use the equation I = I(max) x e^(-t/RC)
we know I(max), R and C so we can find t
t = 0.049 = 0.05 s
part iii - Same curve
c - use the equation V = V(max) x e^(-t/RC)
V will be 0.7 (0.07 of 10 = 0.7)
(If you can't get the answer then tell me and I will show you the full solution)
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16 b iii - Okay, we know that the smaller the wavelength the smaller objects can be investigated and these electrons have that wavelength
iv - use the knowledge of aplha scattering.
Passed through - empty space
scattered at large angles - there are other particles within a proton and those are quarks
KJ1995:
Can someone please tell me how to solve this question: A positron with kinetic energy 2.2MeV collides with electron at rest, annihilation occurs. Whats the average energy of the two gamma photons produced as a result of the annihilation. The other part is to calculate the frequency of these photons.
Thanks in advance!
The Golden Girl =D:
I can help yuh but won't do all the workings (I guess I ain't in the mood :$ )
if you have MeV then this is what you do ;
[2.2 * (1.6 * 10-13)]/[ (3*108)2] = _____ Kg
I think you should multiply by 2 since it's TWO gamma particles.
E = delta m * c2
you find the Energy ..I think that's how you do it :)
Mr.Paul can you please confirm this (:
The Golden Girl =D:
Classify each of the following particles by ticking all the appropriate boxes in the table.
Particle Lepton Baryon Hadron Meson
Neutron, n tick tick
Neutrino, ? tick
Muon, ? tick tick
(Total 3 marks)
they say Neutrino is considered a Lepton okay ..why is that ?
shouldn't it be either Muon neutrino , tau neutrino , or electron neutrino not just the word Neutrino ALONE or I'm misunderstanding something here?
Thanks in Advance (:
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