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Edexcel PHYSICS Doubts

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The Golden Girl =D:
inshAllah :)

High-R:
Inshaa Allah! :)

can any1 plz help me with 2011 phys unit6B (6PH08)
i dont get the Q2 part c ???
and even in Q2 part d how exactly do we do that?
all i know is u find the uncertainity by first finding the mean of the values given and then subtracting the mean from the lowest value(from the set of values given) thats how uncertainity is found right? so its +/- 0.2!!
and what do i do next? ???

High-R:
confused in percentage uncertainity
percentage difference
uncertainity
etc
can u please tell how do u find ALL THESE?
:S
eg: in 2011 unit6b jan paper
Q3(ii) they ask percentage difference so (2.01-1.93)/ 1.97 = 4.1% is the working given in the markscheme, but why did we use 1.97(the mean value)? ???

Master_Key:

--- Quote from: MujtabaM on June 02, 2011, 12:12:56 pm ---Lol the 1st question is the 1st question of the specimen paper  :) See My Diagram Attached

Suppose the resistance of each resistor is 10 ohm......the total R through line 1 will be 10 ohm and the total R through line 2 will be 20 ohm......

So the current through line 2 will be halved( use the equation V=IR if R doubles, I is halved)

So using the Eq: P= I2 x R for line 2 if the current is halved, the P is quartered....D is the answer

lol....i know its tricky but go in sequence and use the right equatons  ;)

http://imageshack.us/photo/my-images/29/physicsl.jpg

--- End quote ---

From kirchoff's laws. Current is never used up. Current entering a circuit equals the current leaving it.

IN SERIES:-
Current is the same across all components and voltage is different across all components.

IN PARALLEL:-
Current is different across different components and voltage is same across all of them. ALL HOUSES AND INDUSTRIES ARE THUS CONNECTED IN PARALLEL TO THE NATIONAL GRID IN ORDER TO GET FULL P.D.

The Golden Girl =D:
Paper Attached.

I've got loads of Qs  :-X

hmm can someone explain in section A Qs 4 ,5 , 6

Section B

Qs , 12]b) , 13]a)iii) , 17]b) , 19]a)ii)

Thanks in Advance :D

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