Qualification > Math
C3 and C4 DOUBTS HERE!!!
iluvme:
--- Quote from: Kimo Jesus on September 19, 2011, 01:58:45 pm ---Hi guys , can anyone get me the answers of these questions ? all of them :P
thanks
--- End quote ---
Looks like its your homework :P
You've got any doubts or are all these questions your doubts?
WARRIOR:
--- Quote from: iluvme on September 19, 2011, 02:50:39 pm ---Looks like its your homework :P
You've got any doubts or are all these questions your doubts?
--- End quote ---
well ill be specific in a moment of which questions i need anyway. this is important how do u solve this
find the inverse function of f (x) = 2x + 3/x-1
Arthur Bon Zavi:
--- Quote from: Kimo Jesus on September 19, 2011, 05:05:24 pm ---well ill be specific in a moment of which questions i need anyway. this is important how do u solve this
find the inverse function of f (x) = 2x + 3/x-1
--- End quote ---
Let f-1(x) be y and y, x.
y = (2x + 3) / (x - 1)
y (x - 1) = (2x + 3)
yx - y = 2x + 3
yx - 2x = 3 + y
x (y - 2) = 3 + y
x = (3 + y) / (y - 2)
Now replace the values again to get :
f-1(x) = (3 + x) / (x - 2)
WARRIOR:
--- Quote from: Arthur Bon Zavi on September 19, 2011, 05:14:24 pm ---Let f-1(x) be y and y, x.
y = (2x + 3) / (x - 1)
y (x - 1) = (2x + 3)
yx - y = 2x + 3
yx - 2x = 3 + y
x (y - 2) = 3 + y
x = (3 + y) / (y - 2)
Now replace the values again to get :
f-1(x) = (3 + x) / (x - 2)
--- End quote ---
thanks it turned out to be really easy !
WARRIOR:
--- Quote from: Arthur Bon Zavi on September 19, 2011, 05:14:24 pm ---Let f-1(x) be y and y, x.
y = (2x + 3) / (x - 1)
y (x - 1) = (2x + 3)
yx - y = 2x + 3
yx - 2x = 3 + y
x (y - 2) = 3 + y
x = (3 + y) / (y - 2)
Now replace the values again to get :
f-1(x) = (3 + x) / (x - 2)
--- End quote ---
anothr question
what is the range and domain of the inverse that you just got out?
for f(x) the domain is x>1 , x E R
range y >=7
right?
so for f^-1 = should be the opposite?
domain y>=7
range x>1?
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