Qualification > Math

S1 and S2 DOUBTS HERE!!!!

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SkyPilotage:

--- Quote from: melony on May 25, 2011, 08:12:06 pm ---Im not sure but this is how i understood it, this is the first time im looking at it

SO the first three colas are next to each other, [CCC]

lets just let that be one big C, green tea = G, oranje juice = J

there are only three different places we can place the G:

1) G C G J J    2) G C J G J    3) G C J J G

hence the 3

note that the Gs can not be moved the only thing we can move is C J J hence 3! = 4x3/2

therefore 3x3!=18 or as the mark sceme 3x(4x3/2)

hope i helped  ;), good luck everyone im out for the night!

--- End quote ---
By the way Remember! YOu cannOT do 3! only There is a repeated term which is the 2 JJ so It must be 3!/2....Couldnt the G be put 2nd and last? so It would have more than 3 laces to be moved to..Its infact 6! SO its actually 6x3!/2....But what I dont get is why they Did 4x3/2 ?!?!

dj_dead:

--- Quote from: Ghost Of Highbury on May 25, 2011, 09:18:33 am ---I guess the question/question paper you stated isn't the question you are confused about.

Anyway, i dont know the q, but i guess i understand ur doubt.

phi(t) = 0.7389
Meaning, for which value of 't' is the area 0.7389. For this u gotta look at the normal distribution table. You'll find it in the CIE S1 book
and the syl.

I've attached the part of the table where I found 0.7389. If you look closely, you'll see that cell (red) is in the 6th column (starting from column 'z') and the 7th row (starting from 0.0). 0.60 + 0.04 = 0.64,

--- End quote ---



ohhhhhh so DATS how u look at it...i ws lookin at it the other way round.....thankuu soooo veryyyy muchhh =D life saver i tel u :) all d bst wid ur papers bro !

Tohru Kyo Sohma:
can someone pls explain qns 3 p62 oct/nov 2010 CIE!

........:

--- Quote from: mimiswift on May 25, 2011, 11:00:05 pm ---can someone pls explain qns 3 p62 oct/nov 2010 CIE!


--- End quote ---

See the attachment below.

Since this is a conditional probability you find out the probability of getting a 12.

If the spinner is thrown on a even side
then there are 4 ways 12 can come.
and the probability of a spinner landing on 12 would 2/5.
So here is Probability of getting a 12 if the spinner lands on the even side
2/5 * 4/36

similarly you do this for the spinner landing on the odd side
which would be 3/5 * 1/36

Now it says it lands on a even side so the fraction should look like this
2/5*4/36
---------
(2/5*4/36)+(3/5*1/36)

Tohru Kyo Sohma:
thank you so much dumb economist!
+rep

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