Author Topic: All Mechanics DOUBTS HERE!!!  (Read 85740 times)

Offline egymoha

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Re: All Mechanics DOUBTS HERE!!!
« Reply #270 on: June 01, 2010, 09:35:50 am »
what about June 2006 8b ?

Offline crazed2009

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Re: All Mechanics DOUBTS HERE!!!
« Reply #271 on: June 02, 2010, 07:01:40 am »
Don't worry mate! Put them in the direction you want, up or down ya wadee3 :P

Caues at last, if you put it in the wrong direction, your answer would be in negative, and you would know ;)

actually A.F tht doesnt always work.. i was also coming to ask the same question - which way do we put the reactional force?????... c this Q:

a window of mass 15kg and height 120cm is hinged along its top edge. It is kept open by the thrust frm a light strut of lenght 50cm attached to the wall and perpindicular to the lower edge of the window. By modelling the window as a uniform lamina, calculate the thrust in the strut and the magnitude an direction of the force exerted on the window by the hinge? (u hv to draw the diagram)

i attached the answer... i got T but i dnt really understand the rest.. :S...
y is the reactional force acting upwards meaning tht at the hinge the horizontal force is to the left and the vertical force is upwards???? if u put them any other way the correct answer doesnt cm... :S:SS:
\HELP PLEEEEEEEEEEEEZ

Offline Meticulous

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Re: All Mechanics DOUBTS HERE!!!
« Reply #272 on: June 02, 2010, 08:15:12 am »
I apologize everybody for the delay! I'm on it now :)

« Last Edit: June 02, 2010, 08:19:07 am by ~ A.F ~ »

Offline Meticulous

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Re: All Mechanics DOUBTS HERE!!!
« Reply #273 on: June 02, 2010, 08:59:25 am »
what about June 2006 8b ?

First of all:

VB = u(e+1)/5

And e between B and the wall = 4/5

Therefore, the velocity of B after rebounding= 4/5 * u(e+1)/ 5 = 4u(e+1)/25

There is a further collision between A and B, and so VBrebound > VA

PLUS, VA > 0 -----> u(4e-1)/5 >0 and so e>1/4

here is a further collision between A and B, and so VBrebound > VA :
 
e<9/16

combine the two inequalities to give you

1/4 < e < 9/16

Was I clear ::) ?



« Last Edit: June 02, 2010, 09:01:19 am by ~ A.F ~ »

Offline Meticulous

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Re: All Mechanics DOUBTS HERE!!!
« Reply #274 on: June 02, 2010, 09:04:49 am »
actually A.F tht doesnt always work.. i was also coming to ask the same question - which way do we put the reactional force?????... c this Q:

a window of mass 15kg and height 120cm is hinged along its top edge. It is kept open by the thrust frm a light strut of lenght 50cm attached to the wall and perpindicular to the lower edge of the window. By modelling the window as a uniform lamina, calculate the thrust in the strut and the magnitude an direction of the force exerted on the window by the hinge? (u hv to draw the diagram)

i attached the answer... i got T but i dnt really understand the rest.. :S...
y is the reactional force acting upwards meaning tht at the hinge the horizontal force is to the left and the vertical force is upwards???? if u put them any other way the correct answer doesnt cm... :S:SS:
\HELP PLEEEEEEEEEEEEZ

Pls post the original q to see if i have the answer to it, and save time ;)

Offline crazed2009

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Re: All Mechanics DOUBTS HERE!!!
« Reply #275 on: June 02, 2010, 10:15:53 am »
its a txtbk question ...  :-X

Offline raimunts

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Re: All Mechanics DOUBTS HERE!!!
« Reply #276 on: June 04, 2010, 08:38:48 pm »
Hello. Can someone PLEASE help me solve these two kinematics questions? They are from the Edexcel AS Modular Mathematics M2 book:
Edexcel AS Modular Mathematics M2
Ex.1A No. 16, page: 11
Ex.1B No. 12, page: 19

Any help will be really appreciated. Thanx a lot in advance!

Offline raimunts

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Re: All Mechanics DOUBTS HERE!!!
« Reply #277 on: June 05, 2010, 08:47:47 am »
Someone please help me fast! It's urgent! Pleaaase!!  :(

Offline cooldude

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Re: All Mechanics DOUBTS HERE!!!
« Reply #278 on: June 05, 2010, 01:00:15 pm »
Hello. Can someone PLEASE help me solve these two kinematics questions? They are from the Edexcel AS Modular Mathematics M2 book:
Edexcel AS Modular Mathematics M2
Ex.1A No. 16, page: 11
Ex.1B No. 12, page: 19

Any help will be really appreciated. Thanx a lot in advance!

if u posted the question there is a higher probability you would get the answer as the textbook you are referring to, is not in the possession of every person who has the capability of answering your doubt

Offline 7ooD

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Re: All Mechanics DOUBTS HERE!!!
« Reply #279 on: June 05, 2010, 06:02:56 pm »
for my doubt about where to put the directions if hinged at a wall u can put in the moment equation wiz its minus sign and in the direction u assumed but if u dnt put minus sign make sure u put it in the direction u found from da equation
pimpin ain't dead it just moved to the web



Offline 3oo3a

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Re: All Mechanics DOUBTS HERE!!!
« Reply #280 on: June 10, 2010, 05:44:32 pm »
hello!
I couldn't find the answer of question 8 (c) january 2010 paper on the internet, i tried finding it alone, and i got (5i)(c^2 +1)

anyone got the same? :)

Offline 7ooD

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Re: All Mechanics DOUBTS HERE!!!
« Reply #281 on: June 10, 2010, 05:51:36 pm »
i will give it now 1 min
pimpin ain't dead it just moved to the web




Offline shushuIG

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Re: All Mechanics DOUBTS HERE!!!
« Reply #283 on: June 11, 2010, 02:26:55 am »
ould anyone plz help me in jan 2010 in Q4 and 6 plz?? i need it ASAP exam in 2 hours!!:S

Offline astarmathsandphysics

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Re: All Mechanics DOUBTS HERE!!!
« Reply #284 on: June 11, 2010, 08:09:26 am »
Let me get up.