Qualification > Math
All Mechanics DOUBTS HERE!!!
cashem'up:
--- Quote from: Khey on May 04, 2010, 05:53:13 pm ---Thanks to "nid404" and "the mysterious dude"
but both of u have differnt answers so m confused bout who's answer is right..but its alryt i will ask my teacher
once again Thanks alot ;D
--- End quote ---
no i am pretty sure nid404 is correct because to find the the Normal Contact u have to find the resulting vertical downward force that box exerts on ground and then the normal will be same as that.
If u also think logically when ur pulling something at such an angle u will be lifting some of the weight off........ dont take this literally but logically so less force will be exerted on the ground...... u get wat i am saying
cashem'up:
--- Quote from: halosh92 on May 04, 2010, 04:10:08 pm ---two particles P and Q of masses 1kg and 2kg respectively are hanging from the ends of alight inextensible string which passes over a smooth fixed pulley. the system is released from rest with both particles a distance 1.5m above a floor. when the masses have been moving fir 0.5 s the string breaks. find the furthur time that elapses before P hits the floor
??? ??? ??? ??? ??? ??? ??? ??? ??? ??? ???
--- End quote ---
hey halosh is the answer possibly 1.01 seconds
cashem'up:
--- Quote from: halosh92 on May 05, 2010, 06:07:23 pm ---a particle A of mass "m" which can move on the rough surface of an inclined plane at an angle X to the horizontal.
where X=arcsin 0.6
a second particle B of mass "2m" hangs freely attached to a light inextensible string which passes over a smooth pulley fixed at P. the other end of the string is attached at A . the coefficient of friction between A and the plane is 1/4.
B is initially hanging 1m above the ground and A is 2m from the pulley. when the system is released from rest with the string taut A moves up the plane
a) find the initial acceleration of A
b) calculate the total distance moved by A before it first comes to rest.
--- End quote ---
answer to (a) should be 4m/s2
and to (b) 1.99 m
if iam correct i will explain , dont want to confuse you with wrong answrs.......:P
halosh92:
--- Quote from: ima_shah2002 on May 05, 2010, 07:50:33 pm --- answer to (a) should be 4m/s2
and to (b) 1.99 m
if iam correct i will explain , dont want to confuse you with wrong answrs.......:P
--- End quote ---
this is the exact answer:
3.92 m/s
1.5 m
thankyou ;D
immortal:
--- Quote from: The Mysterious Dude on May 04, 2010, 05:33:39 pm ---here u go.
--- End quote ---
using this method i got a different ans.
u=0.3997
200cos30-(u*(40g-200sin30)=40a
a=1.33
If i replace da red wit 150sin30, i get ur ans.
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