Qualification > Math

C1 and C2 DOUBTS HERE!!!!!

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vanibharutham:
Just divide your large value by some of the common squares - 4, 9, 16, 25, 36, 49.... etc..
they wont give u something so hard in the exam :)

Blizz_rb93:
oh okay lol thanks :D

Blizz_rb93:
Hi
I got this question regarding Trigonometry equation solving..

Here's the question:

Solve for 0 < x < 180, the equation:
a) Sin(x+10) = (Square root of 3) / 2
b) cos2x = -0.9, giving your answers to 1 decimal place

Thing is i dont get how do u find questions when they got parts like that where they want sin(x+10 degrees ) :s

Saladin:

--- Quote from: Psyclax on May 15, 2010, 12:27:41 pm ---Hi
I got this question regarding Trigonometry equation solving..

Here's the question:

Solve for 0 < x < 180, the equation:
a) Sin(x+10) = (Square root of 3) / 2
b) cos2x = -0.9, giving your answers to 1 decimal place

Thing is i dont get how do u find questions when they got parts like that where they want sin(x+10 degrees ) :s

--- End quote ---

Which paper did you take them from. That way, I can check my answers.

immortal:

--- Quote from: Psyclax on May 15, 2010, 12:27:41 pm ---Hi
I got this question regarding Trigonometry equation solving..

Here's the question:

Solve for 0 < x < 180, the equation:
a) Sin(x+10) = (Square root of 3) / 2
b) cos2x = -0.9, giving your answers to 1 decimal place

Thing is i dont get how do u find questions when they got parts like that where they want sin(x+10 degrees ) :s

--- End quote ---
a) sin(x+10)=(Square root of 3) / 2
    (x+10)=sin-1(Square root of 3) / 2
     (x+10)=60
      x=50
 2nd quadrant    (x+10)=120
                                       x=110

b)cos2x = -0.9
    2x=cos-10.9
    2ndquad   2x=180-25.84                         3rdquad      2x=180+25.84
                                   x=77.1                                                                  x=102.9                   
   

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