Qualification > Sciences

P1 CIE physics doubts

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nid404:
Thanks A.F :) + rep

astarmathsandphysics:
I think I remember the question. Use 1/r=1/100+6x1/100/ on a phone now

~ A.F ~:
Thanks Nid :D

Saladin:
I remember this question too, and I could answer it myself, but this is the problem, I dont think that would practically happen. Does this thing practically happen sir??

Its kinds hard for me to take in also.

I got it like this, reducing the diameter will reduce resistance, but since the wires are in paralell, that will even out. What I have a hard time swallowing is if this would really happen.

sweetie:

--- Quote from: ~ A.F ~ on April 28, 2010, 03:37:02 pm ---Here's ur explanation guys:

Resistance of P= pl/A...agree?

Resistance of Q:

Area of each wire of the seveen wires= A/7...right?

now R=pl/A= pl/(A/7)= 7pl/A...so far so good..thats the are for each wire..

now total area of resistor Q:

RT = (1/R1 + 1/R2 ....)-1

=(1/(7pl/A) x7)-1 = pl/A

hope that's clear now

--- End quote ---

yup, now iam convinced  :)
thanx A.F

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