P1 CIE physics doubts

[dodo]

sorry what's the value for the pi plz
and what's pi???/

[nid404]

pi radians = 180 degrees

one whole period corresponds to 2pi radians or 360 degrees...
For constructive interference they have to be in phase
For destructive interference they have to be out of phase...and for minima to have a value of zero...they should have a phase diff of pi or all odd multiples of pi

[sweetie]

10 approach speed=u1+u2
separation speed=v2-v1
they are equal for elastic collisions  D
11.res for both particles using F=ma
for 2g particle 2g-T=2a (1)
for 6g particle T-6=6a (2)
(1) +(2) 2g-6=8a so a/(2*9.8-6)/8=1.7 B
32)1/R=1/100+1/10+1/10+1/10+1/10+1/10+1/10=61/100
R=100/61 B

Thank You 
but i just wanted 2 know how do we know that the wires r connected in parallel in Q32?

[nid404]

Thank You 
but i just wanted 2 know how do we know that the wires r connected in parallel in Q32?

yes all of them parallel to each other

[dodo]

hey agian am really sorry but how did u get 18.7and 11.2??? sorrrrrrrrrrrrrrrrrrrrrrrrrrrryyyyyyyyyyyyyyyyyyyyyyyy

[nid404]

hey agian am really sorry but how did u get 18.7and 11.2??? sorrrrrrrrrrrrrrrrrrrrrrrrrrrryyyyyyyyyyyyyyyyyyyyyyyy

lol....it's ok

substitute for different phase difference...in the first case phase diff is pi, followed by 3pi,5pi,7pi ...like i said for destructive interference, it has to be an odd multiple of pi..

substitute these in the eqn to get wavelength.. phase diff= 2pi/ lambda  X path diff
for phase diff     wavelength/lambda
      pi                   56
      3pi                 18.7
      5pi                 11.2
      7pi                  8

hope ur getting it

[dodo]

sorry i get the pi=56 but the 3pi is not coming out could u plz wirte it in numbers because is not coming
thx really ur so helpful

[nid404]

sorry i get the pi=56 but the 3pi is not coming out could u plz wirte it in numbers because is not coming
thx really ur so helpful

no problem

for 3pi

wavelength= 2pi/3pi X 28
               = 2/3 X 28
               =18.7

got it?

[~ A.F ~]

A-W-E-S-O-M-E Nid! You're awesome!

+ rep.

[sweetie]

 CUD SUM1 PLZ XPLAIN THESE 2 QUE'S??

may 06
Q.35
Q36

[nid404]

A-W-E-S-O-M-E Nid! You're awesome!

+ rep.

yay!! 

I finally got waves...thanks to you 

[nid404]

CUD SUM1 PLZ XPLAIN THESE 2 QUE'S??

may 06
Q.35
Q36

Q 35

one i've circled are in series...
10+10+10=30ohms
these are all parallel to the 10 ohm resistor
1/30 +1/10= 1/R
R approx 7.5 ohms
between 1 and 10 ...B

[nid404]

Q36

It's the same diagram both of them..
in diagram 1

4 lamps...2 in series..parallel with 2 other is series on the same side of the source

diagram 2

4 lamps 2 in series parallel with 2 other on the other side of the source...

so they're just twisting the diagram...no difference on brightness...

[sweetie]

Thank You nid 
+rep

cud u also xplain Q33 and 9 of the same year

[astarmathsandphysics]

9, B cos it is the biggest negative gradient
33. Across the top the voltage splits in ration 1:2 ie 4V:8V
but accross the bottom it is 8:V:4V
so Potential differenceD is 4V